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云凌霜1993

金虫 (小有名气)

[求助] matlab 曲线拟合的问题,拜托了

求助大家,通过实验数据得出了一系列C和F,如何通过matable拟合出指定方程C= 1-exp(-k/F)里头的K值呢?从别人那里要来的代码计算总出现错误,真心看不懂。
Undefined function or method 'eval' for input arguments of type 'double'.

Error in ==> main>zuixiao at 40
   y(i)=eval(C1)*100;%  (corresponding output)

Error in ==> fmincon at 540
      initVals.f = feval(funfcn{3},X,varargin{:});

Error in ==> main at 11
k1 = fmincon(@zuixiao,[0],[],[],[],[],0,[],[]);

Caused by:
    Failure in initial user-supplied objective function evaluation. FMINCON cannot continue.

??? Undefined function or method 'eval' for input arguments of type 'double'.
代码贴在这里了,拜托大家了!!!
function main()
clear all
close all
warning off
syms k F C
data=[0.0153        99.91
0.0244        99.72
0.0312        99.31
0.0463        97.82];% (figure)
C= 1-exp(-k/F) ;% (defined formula)
k1 = fmincon(@zuixiao,[0],[],[],[],[],0,[],[]);
C=subs(C,k,k1) ;% current value
disp(['The corresponding expressions for:' ])
disp(vpa(C,4))
x=0.01:0.001:0.05;
for i=1:length(x)
    Temp=subs(C,F,x(i)) ;
    y(i)=eval(Temp)*100;
end
figure('color',[1 1 1])
scatter(data(:,1),data(:,2),'.')
hold on
plot(x,y)
xlabel('Flux(mL/cm^2s)')
ylabel('Conversion %')
legend('Experimental','Fitted curve')
box on
function error=zuixiao(x)
syms k F C
data=[0.0153        99.91
0.0244        99.72
0.0312        99.31
0.0463        97.82];% (figure)
C=1-exp(-k/F);% (defined formula)
C=subs(C,k,x);% (current value)
m=length(data(:,1));
error=0;%  (initial error)
for i=1:m
   C1=subs(C,F,data(i,1));
   y(i)=eval(C1)*100;%  (corresponding output)
   error =error+(y(i)-data(i,2))^2;% (square error)
end
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sdwawa

铜虫 (初入文坛)

为什么要拟合呢?看公式k=-Fln(1-C)。直接代数据进去算完后再统计平均不可以吗?matlab也很好实现

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2楼2017-06-09 10:46:45
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云凌霜1993

金虫 (小有名气)

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引用回帖:
2楼: Originally posted by sdwawa at 2017-06-09 10:46:45
为什么要拟合呢?看公式k=-Fln(1-C)。直接代数据进去算完后再统计平均不可以吗?matlab也很好实现

因为数据有限,拟合出来应该会更准确一点

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3楼2017-06-09 15:22:09
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zhangjiangbo

木虫 (正式写手)

4楼2017-06-10 22:32:01
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