2楼: Originally posted by
alober at 2016-11-27 22:16:34
I=\int\frac{x-1+1}{(1-x)^3}dx=\int\frac{1}{(1-x)^3}dx-\int\frac{1}{(1-x)^2}dx=-\int\frac{1}{(1-x)^3}d(1-x)+\int\frac{1}{(1-x)^2}d(1-x)=\frac{1}{2}(1-x)^{-2}-(1-x)^{-1}+C
I=\int(\sin x\sin 3x)\sin 2x ...
回复此楼
枫飛