10Â¥: Originally posted by Edstrayer at 2016-06-09 03:32:09
µ±a_k=(-1)^{\frac{k(k-1)}{2}}\frac{1}{k}ʱ£¬
¼¶Êý\sum\limits_{k=1}^{+\infty}a_k·¢É¢£¬
µ«ÊǼ¶Êý\sum\limits_{k=1}^{+\infty}\frac{a_k}{k}¾ø¶ÔÊÕÁ²¡£

5Â¥: Originally posted by iάÊý at 2016-06-09 03:19:32
àÅ£¬ÕâЩÇé¿ö¶¼ºÜ¼òµ¥£¬¹Ø¼üÊÇÒª¿¼ÂÇa_kΪһ°ãÏÊý»òÕßÔ­¼¶ÊýÌõ¼þÊÕÁ²µÄÇé¿ö¡£...

13Â¥: Originally posted by vect at 2016-06-09 08:40:58
38¸öÊÕÁ²£¬ÓÃDirichletÅб𷨣ºÁ½¸öÒò×ӳ˻ýµÄ¼¶Êý£¬Ò»¸öÒò×Óµ¥µ÷Ç÷ÏòÓÚ0£¬ÁíÒ»¸öÒò×ӵļ¶ÊýÒ»ÖÂÓн磨ÊÕÁ²ÏÔÈ»Óн磩£¬ÔòÔ­À´µÄÊÕÁ²

12Â¥: Originally posted by hank612 at 2016-06-09 04:11:03
Edstrayer  iάÊý

Æäʵ, ÕýÏÊý¿ÉÒÔÇáÒ×Íƹ㵽 Ò»°ãÏÊýµÄ.

Àî´úÌÒ½©´ó·¨, µ±µ±µ±µ±(3)

ÉèÐòÁм«ÏÞΪA. ÈôA²»µÈÓÚ0, ¿¼ÂÇ ÐÂÐòÁÐ b_n=\frac{a_n}{A}, ·ñÔò, ÈÃb_n=a_n+\frac{1}{2^n}, ²¢ÇÒÈÃS_n=\su ...

16Â¥: Originally posted by ¹þ¹þЦÄà at 2016-06-09 17:19:33
39£¬´í
an=1/n

17Â¥: Originally posted by ¹þ¹þЦÄà at 2016-06-09 17:24:47
¡Æ1/(n¡¤n¡Ä1/n)£¬ÊÕÁ²Âð£¿
...

18Â¥: Originally posted by ¹þ¹þЦÄà at 2016-06-09 17:27:30
´íÁË£¬°¥£¬·¢É¢£¡
...

19Â¥: Originally posted by ¹þ¹þЦÄà at 2016-06-09 17:36:37
39£¬ÕýÈ·
...