ansys 后处理问题!!!
进行了管道应力仿真(管道内径90,mm,外径98mm),得到应力分布图之后,查看半径92mm上圆柱面的应力分布图,结果如下图所示,我想把圆柱面展开成一个矩形平面怎么办!!!各位大神帮忙啊~~
附带我的代码
finish
/clear
/prep7
R1=0.09
R2=0.098
L=1
ET,1,SOLID185
MP,EX,1,2.1E11
MP,PRXY,1,0.3
MP,DENS,1,7800
csys,1
*AFUN,DEG
CYL4,0,0,R1,0,R2,360,L
MSHAPE,1,3D
MSHKEY,0
ESIZE,0.01
VMESH,1
*GET,ENUM1,ELEM,0,NUM,MAX
!wpcsys,,0 工作平面复位
/solu
DA,1,UZ,0
DA,1,UY,0
DA,2,UY,0
SFA,5,1,PRES,4E6
SFA,6,1,PRES,4E6
SFA,2,1,PRES,-11.75E6
solve
/POST1
rsys,1
PLNSOL,S,x,0,1.0
/cplane,1
sucr,mid,infc,,0.092,,,,
sumap,dimplot,s,x
supl,mid,dimplot
![ansys 后处理]()
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