2楼: Originally posted by feixiaolin at 2015-10-26 22:05:19
http://wenda.haosou.com/q/1371374279060673

Function  N=k*p^d;
Data;
N=[457337,195025,86695,56388,47778,15839,12072];
p=[0.95,1.31,1.50,1.71,1.92,2.15,2.63];

4楼: Originally posted by dingd at 2015-10-27 09:58:00
图方便简单用1stOpt，两句话：

Function  N=k*p^d;
Data;
N=;
p=;


均方差(RMSE):16214.9390890685
残差平方和(SSE):1840469747.63542
相关系数(R): 0.994259378348237
相关系数之平方(R^2): 0.988551 ...

5楼: Originally posted by Integrity02 at 2015-10-27 13:36:12
数据处理时提示，待处理数据长度不够

D5Z)GZY6$~$T1I2T$`5M_9N.png
...

Variable N,P;
Function  N=k*p^d;
Data;
457337        0.95
195025        1.31
86695        1.50
56388        1.71
47778        1.92
15839        2.15
12072        2.63

6楼: Originally posted by dingd at 2015-10-27 15:35:47
老版本的话这样写试试：

Variable N,P;
Function  N=k*p^d;
Data;
457337        0.95
195025        1.31
86695        1.50
56388        1.71
47778        1.92
15839        2.15
12072        2.63
...