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B2P(1) ans = 2 1/2 / -0.005000000000 (0.000899999999999999975 - X1 ) / ( / 2 (-0.0299999999999999989 cos(t) - X1) + 0.00002500000000 + 2 1/2 2 (-0.0299999999999999989 sin(t) - (0.000899999999999999975 - X1 ) ) )^ 3/2 int(B2P(1),X1) ans = / | 2 1/2 / | -0.005000000000 (0.000899999999999999975 - X1 ) / ( | / / 2 (-0.0299999999999999989 cos(t) - X1) + 0.00002500000000 + 2 1/2 2 (-0.0299999999999999989 sin(t) - (0.000899999999999999975 - X1 ) ) )^ 3/2 dX1 Çó·ûºÅ»ý·Ö£¬ ½á¹ûÈÔÓÐX1? Çó½â |
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