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赵奇一

新虫 (小有名气)

[求助] QE的一个例子不是太理解,求解释

在研究例子中对这两个过程的区别不是太清楚,求解释一下:
# self-consistent calculation
cat > al001.rx.in << EOF
&CONTROL
  calculation = "relax",
  pseudo_dir  = "$PSEUDO_DIR",
  outdir      = "$TMP_DIR",
/
&SYSTEM
  ibrav       = 6,
  celldm(1)   = 5.3033D0,
  celldm(3)   = 8.D0,
  nat         = 7,
  ntyp        = 1,
  ecutwfc     = 12.D0,
  occupations = "smearing",
  smearing    = "methfessel-paxton",
  degauss     = 0.05D0,
/
&ELECTRONS
  conv_thr    = 1.D-6,
  mixing_beta = 0.3D0,
/
&IONS
  bfgs_ndim         = 3,
/
ATOMIC_SPECIES
Al  1.0  Al.pz-vbc.UPF
ATOMIC_POSITIONS
Al   0.5000000      0.5000000     -2.121320
Al   0.0000000      0.0000000     -1.414213
Al   0.5000000      0.5000000     -0.707107
Al   0.0000000      0.0000000      0.000000
Al   0.5000000      0.5000000      0.707107
Al   0.0000000      0.0000000      1.414213
Al   0.5000000      0.5000000      2.121320
K_POINTS
3
0.125  0.125  0.0  1.0
0.125  0.375  0.0  2.0
0.375  0.375  0.0  1.0
关于上边,说明上是说:make a geometry relaxation for a Al (001) slab performing a series of  self-consistent calculations and computing the forces on atoms。
下边这个计算,说明上是这么描述的:make a geometry relaxation for the same Al (001) slab used in step 2  performing a series of self-consistent calculations, computing the   forces on atoms and evolving the atomic positions according to Newton   equation.
# self-consistent calculation
rm -f e eal ave p avec tv
cat > al001.mm.in << EOF
&CONTROL
  calculation = "relax",
  dt          = 30.D0,
  pseudo_dir  = "$PSEUDO_DIR",
  outdir      = "$TMP_DIR",
/
&SYSTEM
  ibrav       = 6,
  celldm(1)   = 5.3033D0,
  celldm(3)   = 8.D0,
  nat         = 7,
  ntyp        = 1,
  ecutwfc     = 12.D0,
  occupations = "smearing",
  smearing    = "methfessel-paxton",
  degauss     = 0.05D0,
/
&ELECTRONS
  conv_thr    = 1.D-7,
  mixing_beta = 0.3D0,
/
&IONS
  ion_dynamics      = "damp",
  pot_extrapolation = "second_order",
  wfc_extrapolation = "second_order",
/
ATOMIC_SPECIES
Al  1.D0  Al.pz-vbc.UPF
ATOMIC_POSITIONS
Al   0.5000000      0.5000000     -2.121320
Al   0.0000000      0.0000000     -1.414213
Al   0.5000000      0.5000000     -0.707107
Al   0.0000000      0.0000000      0.000000
Al   0.5000000      0.5000000      0.707107
Al   0.0000000      0.0000000      1.414213
Al   0.5000000      0.5000000      2.121320
K_POINTS
3
0.125  0.125  0.0  1.0
0.125  0.375  0.0  2.0
0.375  0.375  0.0  1.0
对于两个的区别不是太能理解,希望大神能尽可能详细的解答一下...
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