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注册: 2014-09-18
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专业: 模式识别

[求助] 关于支持向量机的SMO算法伪代码中有一些问题请教大家已有1人参与

CODE:
target = desired output vector
point = training point matrix
procedure takeStep(i1,i2)
if (i1 == i2) return 0
alph1 = Lagrange multiplier for i1
y1 = target[i1]
E1 = SVM output on point[i1] – y1 (check in error cache)
s = y1*y2
Compute L, H via equations (13) and (14)
if (L == H)
return 0
k11 = kernel(point[i1],point[i1])
k12 = kernel(point[i1],point[i2])
k22 = kernel(point[i2],point[i2])
eta = k11+k22-2*k12
if (eta > 0)
{
a2 = alph2 + y2*(E1-E2)/eta
if (a2 < L) a2 = L
else if (a2 > H) a2 = H
}
else
{
Lobj = objective function at a2=L
Hobj = objective function at a2=H
if (Lobj < Hobj-eps)
a2 = L
else if (Lobj > Hobj+eps)
a2 = H
else
a2 = alph2
}
if (|a2-alph2| < eps*(a2+alph2+eps))
return 0
a1 = alph1+s*(alph2-a2)
Update threshold to reflect change in Lagrange multipliers
Update weight vector to reflect change in a1 & a2, if SVM is linear
Update error cache using new Lagrange multipliers
Store a1 in the alpha array
Store a2 in the alpha array
return 1
endprocedure
procedure examineExample(i2)
y2 = target[i2]
alph2 = Lagrange multiplier for i2
E2 = SVM output on point[i2] – y2 (check in error cache)
r2 = E2*y2
if ((r2 < -tol && alph2 < C) || (r2 > tol && alph2 > 0))
{
if (number of non-zero & non-C alpha > 1)
{
i1 = result of second choice heuristic (section 2.2)
if takeStep(i1,i2)
return 1
}
loop over all non-zero and non-C alpha, starting at a random point
{
i1 = identity of current alpha
if takeStep(i1,i2)
return 1
}
loop over all possible i1, starting at a random point
{
i1 = loop variable
if (takeStep(i1,i2)
return 1
}
}
return 0
endprocedure
main routine:
numChanged = 0;
examineAll = 1;
while (numChanged > 0 | examineAll)
{
numChanged = 0;
if (examineAll)
loop I over all training examples
numChanged += examineExample(I)
else
loop I over examples where alpha is not 0 & not C
numChanged += examineExample(I)
if (examineAll == 1)
examineAll = 0
else if (numChanged == 0)
examineAll = 1
}
代码见上方，我想请教代码中的return 0和return 1执行后有什么结果？还有E1 = SVM output on point[i1] – y1 (check in error cache)这行代码怎么理解？

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