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急求苯扎氯铵美国药典HPLC含测方法
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 本人急需苯扎氯铵(Benzalkonium Chloride)美国药典HPLC含测方法,查了药典,发现没有HPLC法,用的是滴定法,大家有没有做过HPLC法测苯扎氯铵,要怎样才能查到苯扎氯铵美国药典的HPLC含测方法?:rol先谢过!!!!!!![ Last edited by goodboy520 on 2008-7-20 at 18:04 ] |
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3楼2008-07-24 18:47:16
脂质体
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xy4585618(金币+1,VIP+0):多谢指点
xy4585618(金币+1,VIP+0):多谢指点
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人家USP方法只有滴定法，到哪儿去给你找HPLC方法？HPLC方法也不是药典方法啊！ http://www.google.cn/search?hl=z ... ide%22+HPLC&lr= |
2楼2008-07-20 18:12:03
billy96406
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文献所采用的色谱条件是根据美国药典28版苯扎氯铵中检查各烷基组成比的色谱条件，就是下面的英文原文就是各烷基组成比的检查方法 Ratio of alkyl components— Mobile phase— Adjust a 0.1Msolution of sodium acetate with glacial acetic acid to a pHof 5.0.Mix 55parts of this solution with 45parts of acetonitrile,filter,and degas.The acetonitrile concentration may be varied from 40parts to 60parts to meet system suitability requirements. Standard solution— Dilute USP Benzalkonium Chloride RSwith water to obtain a solution having a known concentration of about 4mg per mL. Test solution— Dissolve about 1g of Benzalkonium Chloride,accurately weighed,in water in a 50-mLvolumetric flask,dilute with water to volume,and mix.Pipet 5.0mLof this solution into a 25-mLvolumetric flask,dilute with water to volume,and mix. Chromatographic system (see Chromatography á621ñ  — The liquid chromatograph is equipped with a 254-nm detector and a 3.9-mm ×30-cm column that contains packing L10.The flow rate is about 2mLper minute.Chromatograph the Standard solution,and record the peak areas as directed for Procedure:the resolution,R,between the C12and C14peaks is not less than 1.5;the column efficiency,determined from the C12peak,is not less than 1000theoretical plates;and the relative standard deviation for replicate injections is not more than 2.0%determined from the C12peak. Procedure— Inject about 20µLof the Test solutioninto the chromatograph,record the chromatogram,and measure the peak areas.Identify the homolog peaks by comparison of the retention times with those from the Standard solution,similarly chromatographed.Calculate the percentage of each quaternary ammonium homolog taken by the formula: 100(A/B), in which Ais the product of the area obtained from the homolog multiplied by its molecular weight;and Bis the sum of all of these products.The molecular weights of the C10,C12,C14,and C16homologs are 312,340,368,and 396,respectively. |
4楼2008-07-25 09:04:50