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moxiaolan33

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[求助] 怎样配制0.2mol/L PH6.6 的磷酸缓冲溶液

从网上查到的方法是
1、磷酸盐缓冲液PB  0.2mol/L磷酸盐缓冲液(PBS)
A液(0.2mol/L NaH2PO4):称取NaH2PO4•H2O 27.6g(或NaH2PO4•2H2O31.2g),溶于蒸馏水中,最后补加蒸馏水至1000ml。
B液(0.2mol/L Na2HPO4):称取Na2HPO4•7H2O53.6g(或Na2HPO4•12H2O 71.6g,或Na2HPO4•2H2O35.6g),加蒸馏水溶解,最后加水至1000ml。

PBS (pH6.6)=A液  62.5 ml + B液 37.5ml

实际配制是:
A液(0.2mol/L NaH2PO4):称取 NaH2PO4•2H2O(分子量156) 3.12g 加100ml 水
B液(0.2mol/L Na2HPO4):称取 Na2HPO4•12H2O 7.16g 加100ml 水

PBS (pH6.6)=A液  62.5 ml + B液 37.5ml

可是配出来PH是7.04  请问这是为什么,怎么解决?
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