| 查看: 552 | 回复: 0 | ||
[求助]
关于MATlAB
|
|
程序如下： clear all; clc; %data = xlsread('E:\nengneng\book1'); %xlsread('E:\nengneng\book1.xls'); Data=load('C:\Users\xing\Desktop\judy\x2.mat') % Data(:,1) % Data(1:10,1) % data(:,1) X=Data.x2(:,1); X_number =size(X) Y=Data.x2(:,2); % Z=Data.x2(:,3); for j=1:41 for i=1:271 Z_Z(i,j)=Z((j-1)*271+i); Z_X(i,j)=X((j-1)*271+i); Z_Y(i,j)=Y((j-1)*271+i); end end % Z_Z % Z_X % Z_Y %划定区域 %Area1~5 Area1=1; Area2=1; Area3=1; Area4=1; Area5=1; for j=1:41 for i=1:271 if Z_X(i,j)<330&&Z_Y(i,j)<250&&Z_X(i,j)>280&&Z_Y(i,j)>200 Area1_point(Area1,  =[i,j];Area1=Area1+1; end if Z_X(i,j)>330&&Z_X(i,j)<380&&Z_Y(i,j)<250&&Z_Y(i,j)>200 Area2_point(Area2, =[i,j];Area2=Area2+1; end if Z_X(i,j)>380&&Z_X(i,j)<550&&Z_Y(i,j)<250&&Z_Y(i,j)>200&&0.56666*Z_X(i,j)-26.666<Z_Y(i,j) Area3_point(Area3, =[i,j];Area3=Area3+1; end if Z_X(i,j)>280&&Z_X(i,j)<380&&Z_Y(i,j)>250&&Z_X(i,j)-15>Z_Y(i,j) Area4_point(Area4, =[i,j];Area4=Area4+1; end if Z_X(i,j)>380&&Z_X(i,j)<550&&Z_Y(i,j)>250&&Z_Y(i,j)<400&&0.56666*Z_X(i,j)-26.666<Z_Y(i,j)&&Z_X(i,j)-15>Z_Y(i,j) Area5_point(Area5, =[i,j];Area5=Area5+1; end end end % Area1_point % Area2_point % Area3_point % Area4_point % Area5_point %计算面积 px1=size(Area1_point); px2=size(Area2_point); px3=size(Area3_point); px4=size(Area4_point); px5=size(Area5_point); px1+px2+px3+px4+px5 AREA1=0; AREA2=0; AREA3=0; AREA4=0; AREA5=0; Circle1=0; Circle2=0; Circle3=0; Circle4=0; Circle5=0; for i=1:px1 I=Area1_point(i,1); J=Area1_point(i,2); Circle1=Circle1+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1)); AREA1=AREA1+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1))*Z_Z(I,J); end for i=1:px2 I=Area2_point(i,1); J=Area2_point(i,2); Circle2=Circle2+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1)); AREA2=AREA2+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1))*Z_Z(I,J); end for i=1:px3 I=Area3_point(i,1); J=Area3_point(i,2); Circle3=Circle3+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1)); AREA3=AREA3+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1))*Z_Z(I,J); end for i=1:px4 I=Area4_point(i,1); J=Area4_point(i,2); Circle4=Circle4+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1)); AREA4=AREA4+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1))*Z_Z(I,J); end for i=1:px5 I=Area5_point(i,1); J=Area5_point(i,2); Circle5=Circle5+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1)); AREA5=AREA5+0.25*(Z_X(I+1,J)-Z_X(I-1,J))*(Z_Y(I,J+1)-Z_Y(I,J-1))*Z_Z(I,J); end %Circle1 Circle2 Circle3 Circle4 Circle5 px1 px2 px3 px4 px5 AREA1 AREA2 AREA3 AREA4 AREA5 % [AREA1 AREA2 AREA3 AREA4 AREA5] % N=100; % x0=linspace(min(x),max(x),N); % y0=linspace(min(y),max(y),N); % [X,Y,Z]=griddata(x,y,z,x0',y0,'v4');%插值拟合曲面。当然，由于你没有说明xy平面上的条件，所以这里拟合的曲面Z=f(X,Y)定义在x0,和y0的矩形区间内； % figure;mesh(X,Y,Z); % Z % %体积的近似值用下代码 % L=sum(sum(abs(Z))); % S=abs((y0(2)-y0(1))*(x0(2)-x0(1))); % V=L*S; %体积 最后运行显示 Data = data: [12195x3 double] ??? Reference to non-existent field 'x2'. 求指教 |
回复此楼» 猜你喜欢
时间戳又变了
已经有19人回复
-
建议基金发布提前给出明确的时间点
已经有4人回复
-
filecode，4个jtjc了
已经有14人回复
-
看来今天不会放榜了？
已经有9人回复
-
让我中一个面上吧！
已经有13人回复
-
人气不行了
已经有7人回复
-
今日不放榜？网传国自然预计 8 月 27 日可查结果
已经有18人回复
-
感觉是下周放榜了
已经有12人回复
-
我面上完蛋了
已经有8人回复
-
只有每年这种时候来逛逛小木虫
已经有25人回复
40