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[求助]
汉译英,求润色,不到100字。谢谢
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表1为样品LS和KS在不同温度下的硬度值和模量值。样品LS的模量要高于样品KS,而硬度则低于样品KS。样品的模量与硬度出现反向相关性,为了表征模量和硬度的综合性能,采用M*H表示样品的综合效能。 Table 1 was the modulus and hardness of sample LS and KS in different temperature. The modulus of sample LS was higher than sample KS, and the hardness lower than sample KS. It is a reverse correlation between the modulus and hardness. In order to characterize the overall performance of the modulus and hardness, the use of M*H express comprehensive effectiveness. |
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phu_grassman
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RXMCDM: 金币+1, 多谢应助! 2014-07-11 12:53:55
wxqtjw: 金币+20, 翻译EPI+1, ★★★★★最佳答案 2014-07-11 13:02:04
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wxqtjw: 金币+20, 翻译EPI+1, ★★★★★最佳答案 2014-07-11 13:02:04
| Table 1 shows the modulus and hardness of Sample LS and Sample KS at different temperature. The modulus of Sample LS is higher than that of Sample KS, while Sample LS has a lower hardness than Sample KS. That is to say, there is a negative correlation between the modulus and the hardness . The value of M*H was used to estimate the comprehensive performance of the samples. |
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