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老男孩5186

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[求助] ΔrUm的求解 已有1人参与

在绝热、恒压、W'=0的条件下,反应 H2(g)+0.5O2(g)→H2O(g) 过程的温度由25℃上升到5313.34℃。则此反应的ΔrUm=( )。 求高手帮助~
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质能守恒1995

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【答案】应助回帖

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xiaoxususy: 金币+3, 欢迎新虫,多多交流 2014-07-08 19:57:47
U=H-pV
dU=dH-d(pV)=dH-pdV
该过程等压无W’,所以dH=δQ,
又因为过程绝热,所以δQ=0,
所以dU=-pdV   积分后可以得
ΔU=-pΔV=pV1-pV2=nRT1-nRT2
所以ΔUm=RT1-RT2

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2楼2014-07-05 15:09:04
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质能守恒1995

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【答案】应助回帖

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老男孩5186: 金币+5, ★有帮助 2014-07-08 17:12:57
引用回帖:
2楼: Originally posted by 质能守恒1995 at 2014-07-05 15:09:04
U=H-pV
dU=dH-d(pV)=dH-pdV
该过程等压无W’,所以dH=δQ,
又因为过程绝热,所以δQ=0,
所以dU=-pdV   积分后可以得
ΔU=-pΔV=pV1-pV2=nRT1-nRT2
所以ΔUm=RT1-RT2
...

最后那里错了一点,前后的n不一样,你自己算一算就知道了

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3楼2014-07-05 20:19:30
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