| 查看: 1781 | 回复: 5 | ||||
| 当前只显示满足指定条件的回帖，点击这里查看本话题的所有回帖 | ||||
kobybry_cn铜虫 (初入文坛)
|
[求助]
这个程序求多重分形维数对吗 已有2人参与
|
|||
|
clc; clear all; close all; %% %indata=inputdlg({'dla'}); a = imread('1.jpg');%%%%此处的1.jpg就是一条直线 [rows, cols] = size(a); figure;imshow(a); npix = sum(sum(a)); %% calculates niL which is the number of pixels in the ith box of size L % ideas from boxcount.m by F. Moisy have been borrowed here width = rows; p =log(width)/log(2); max_boxes = power(rows,2)/power(2,2); nL = double(zeros(max_boxes,p)); for g=(p-1):-1:0 siz = 2^(p-g); sizm1 = siz - 1; index = log2(siz); count = 0; for i=1:siz  width-siz+1)for j=1:siz width-siz+1)count = count + 1; sums = sum(sum(a(i:i+sizm1,j:j+sizm1))); nL(count,index) = sums; end end end %% qran = 1; logl = zeros(p,1); for l=1:p logl(l) = log(power(2,l)); end %% normalized masses pL = double(zeros(max_boxes,p)); for l=1:p nboxes = power(rows,2)/power(power(2,l),2); norm = sum(nL(1:nboxes,l)); if(norm ~= npix) display('error'); end for i=1:nboxes pL(i,l) = nL(i,l)/norm; end end %% %falpha, alpha for l=1:p count = 0; nboxes = power(rows,2)/power(power(2,l),2); for q =-qran:+0.1:qran %denominator of muiql qsum = 0.0; for i=1:nboxes if(pL(i,l) ~= 0) qsum = qsum + power(pL(i,l),q); end end fqnum = 0.0; aqnum = 0.0; smuiqL = 0.0; for i=1:nboxes if(pL(i,l) ~= 0) muiqL = power(pL(i,l),q)/qsum; fqnum = fqnum + (muiqL * log(muiqL)); aqnum = aqnum + (muiqL * log(pL(i,l))); smuiqL = smuiqL + muiqL; end end if(uint8(smuiqL)~=1) display('error'); end count = count + 1; fql(l,count) = fqnum; aql(l,count) = aqnum; qval(count) = q; end end %% % alpha_q for i=1:count line = polyfit(logl,aql(:,i),1); aq(i) = line(1); yfit = polyval(line,logl); sse = sum(power(aql(:,i)-yfit,2)); sst = sum(power(aql(:,i)-mean(aql(:,i)),2)); ar2(i) = 1+(sse/sst); end % f_q for i=1:count line = polyfit(logl,fql(:,i),1); fq(i) = line(1); yfit = polyval(line,logl); sse = sum(power(fql(:,i)-yfit,2)); sst = sum(power(fql(:,i)-mean(fql(:,i)),2)); fr2(i) = 1+(sse/sst); end figure;plot(aq,fq,'r  ');xlabel('\alpha(q)','FontSize',14); ylabel('f(q)','FontSize',14); [ Last edited by kobybry_cn on 2014-1-13 at 22:20 ] |
回复此楼» 收录本帖的淘帖专辑推荐
 资源收集 | 科研辅助-咔咔小男人 |
» 猜你喜欢
售SCI文章，我:8O5.5.1.O.54,科目齐全,可+急
已经有4人回复
-
小木虫上这么多卖论文的，真有人买论文么？感觉没必要啊
已经有12人回复
-
售SCI文章，我:8O.5.5.1O.54,科目全,可十急
已经有4人回复
-
售SCI一区文章，我:8O5.5.1.O5.4,科目全,可伽急
已经有4人回复
-
各位道友，我要去昆明玩几天，回来见。
已经有8人回复
-
售SCI一区T0P文章，我:8O.55.1.O.5.4,科目齐全,可+急
已经有4人回复
-
售SCI文章，我:8O5.5.1.O.54,科目齐全,可+急
已经有5人回复
-
售SCI一区T0P文章，我:8.O55.1.O.54,科目全,可十急
已经有7人回复
-
售SCI一区文章，我:8O5.5.1.O5.4,科目全,可伽急
已经有5人回复
-
售SCI一区T0P文章，我:8.O.55.1.O.54,科目齐全,可+急
已经有8人回复
6楼2015-11-09 12:33:21
戴钢盔的猪头
木虫 (知名作家)
- 应助: 200 (高中生)
- 金币: 5083.9
- 散金: 1310
- 红花: 18
- 帖子: 6001
- 在线: 319.9小时
- 虫号: 2854040
- 注册: 2013-12-07
- 性别: GG
- 专业: 波谱分析与成像分析
3楼2014-01-24 18:59:31
kobybry_cn
铜虫 (初入文坛)
- 应助: 0 (幼儿园)
- 金币: 199.6
- 散金: 20
- 帖子: 22
- 在线: 6.1小时
- 虫号: 2215981
- 注册: 2012-12-31
- 性别: GG
- 专业: 控制论中的数学方法
4楼2014-01-25 23:00:59
5楼2014-03-10 09:44:43
