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xiesen8773

金虫 (小有名气)

[交流] 请问这篇文献中他是怎么把PH调节到9.5的,直接用水稀释吗,还是加酸? 已有5人参与

The mixed MnOx-CeO2 binary oxide catalysts were prepared by coprecipitation involving the surfactant cetyltrimethyl-ammonium bromide (CTAB) in the process. Take the sample with a Mn/Ce ratio of 5:5 as an example: 0.01 mol of Mn(CH3COO)2 ·4H2O and 0.01 mol of
Ce(NO3)3 ·6H2O were simultaneously dissolved in 150 mL of distilled H2O, and 0.008 mol of CTAB was dissolved in 100 mL of distilled H2O. Then, the two kinds of solutions were mixed under stirring, giving a clear homogeneous solution, which was continuously stirred for 2 h. Afterward, about 30 mL of 2 M NaOH solution was quickly added under vigorous stirring to form a solid precipitate. The pH was adjusted to
around 9.5.请问这篇文献中他是怎么把PH调节到9.5的,直接用水稀释吗,还是加酸?

[ Last edited by 王晓萌 on 2013-12-27 at 20:31 ]
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xiesen8773

金虫 (小有名气)

引用回帖:
6楼: Originally posted by a22s at 2013-12-29 00:43:24
原文中不是说得很清楚吗~~~

加30 mL的2 M NaOH溶液,调节PH至9.5左右。就这么简单呀

仁兄30 mL of 2 M NaOH solution  PH值绝对超9.5了,要加水调节至9.5,恐怕这个水加的有点让人难以接受
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7楼2013-12-29 09:12:11
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xiesen8773

金虫 (小有名气)

引用回帖:
2楼: Originally posted by CCmemory at 2013-12-27 18:14:31
加NaOH溶液

仁兄30 mL of 2 M NaOH solution  PH值绝对超9.5了
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3楼2013-12-27 19:20:15
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peterflyer

木虫之王 (文学泰斗)

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小木虫: 金币+0.5, 给个红包,谢谢回帖
王晓萌: 金币+1, 谢谢分享,欢迎常来! 2013-12-27 20:31:23
加水不可能,真要那样那要加多少水?加了30 mL of 2 M NaOH 后共沉淀生成,此时估计Ph值仍然是呈强碱性的,要将Ph值调至9.5,只有一个可能,就是加酸了,中和反应剩余的NaOH。
4楼2013-12-27 19:29:21
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xiesen8773

金虫 (小有名气)

引用回帖:
4楼: Originally posted by peterflyer at 2013-12-27 19:29:21
加水不可能,真要那样那要加多少水?加了30 mL of 2 M NaOH 后共沉淀生成,此时估计Ph值仍然是呈强碱性的,要将Ph值调至9.5,只有一个可能,就是加酸了,中和反应剩余的NaOH。

我感觉也是
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5楼2013-12-27 19:42:48
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