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江西师大99

新虫 (初入文坛)

[求助] 求大神指导

syms m h epsilon1;
pi=3.1415926535897932
np=1.75;
deg1=42.6075;
deg2=25.1675;
deg3=16.3712;
phi1=60-deg1;
phi2=60-deg2;
phi3=60-deg3;
alpha1=phi1*pi/180;
alpha2=phi2*pi/180;
alpha3=phi3*pi/180;
theta1=pi/3.0-asin(sin(alpha1)/np);
theta2=pi/3.0-asin(sin(alpha2/np));
theta3=pi/3.0-asin(sin(alpha3)/np);
N1=np*sin(theta1);
N2=np*sin(theta2);
N3=np*sin(theta3);
lambda=0.650;
epsilon2=-12;
epsilon3=1;
eq='2*Pi/lambda*sqrt(epsilon1-N^2)*h=m*Pi+arctan((epsilon1*sqrt(N^2-epsilon2))/(epsilon2*sqrt(epsilon[1]-N^2)))+arctan(epsilon1*sqrt(N^2-epsilon3)/(epsilon3*sqrt(epsilon1-N^2)))';
eq1='2*pi*h*sqrt(epsilon1-N1^2)/lambda=(m-1)*pi+atan((epsilon1*sqrt(N1^2-epsilon2))/(epsilon2*sqrt(epsilon1-N1^2)))+atan((epsilon1*sqrt(N1^2-epsilon3))/(epsilon3*sqrt(epsilon1-N1^2)))';
eq2='2*pi*h*sqrt(epsilon1-N2^2)/lambda=m*pi+atan((epsilon1*sqrt(N2^2-epsilon2))/(epsilon2*sqrt(epsilon1-N2^2)))+atan((epsilon1*sqrt(N2^2-epsilon3))/(epsilon3*sqrt(epsilon1-N2^2)))';
eq3='2*pi*h*sqrt(epsilon1-N3^2)/lambda=(m+1)*pi+atan((epsilon1*sqrt(N3^2-epsilon2))/(epsilon2*sqrt(epsilon1-N3^2)))+atan((epsilon1*sqrt(N3^2-epsilon3))/(epsilon3*sqrt(epsilon1-N3^2)))';
[m,h,epsilon1]=solve(eq1,eq2,eq3);
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江西师大99

新虫 (初入文坛)

是关于介质薄膜有效折射率和厚度的计算,求指导
2楼2013-06-20 22:00:45
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