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gyh930912

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[求助] 形成5*5的方阵,分别输出方阵中个元素,上三角和下三角元素的vb代码

各位高手,小弟急需这个代码,如有知道滴,谢谢分享!!!
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  • 2013-05-25 21:39:55, 811.08 K

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魔血奋斗历史

银虫 (小有名气)

感谢参与,应助指数 +1
ben_ladeng: 应助指数-1, 非有效应助,收回应助指数。谢谢理解 2013-05-26 20:59:29
简单,你等一会,我给你编一个发过来
2楼2013-05-25 22:15:29
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魔血奋斗历史

银虫 (小有名气)

不好意思,长时间不玩这个,忘了
3楼2013-05-25 22:23:45
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ausir

木虫 (正式写手)

【答案】应助回帖

感谢参与,应助指数 +1
在 Excel 的VBA 工程中,添加用户模块,按以下方式运行:

Sub Matrix()
Dim theMat(0 To 5, 1 To 5) As Single

Dim s As String, s1 As String, s2 As String, s3 As String, s10 As String, s20 As String, s30 As String

Dim i As Integer, j As Integer

For i = 1 To 5
   For j = 1 To 5
       's = "请输入第" & CStr(i) & "行第" & CStr(j) & "列的数值"
       theMat(i, j) = (i - 1) * 5 + j 'Val(InputBox(s, "")
    Next j
Next i

'MsgBox ("输入完成,按确定后显示输入的阵列。"

s1 = ""
s2 = ""
s3 = ""
For i = 1 To 5
    s10 = ""
    s20 = ""
    s30 = ""
    For j = 1 To 5
        s10 = s10 & Format(theMat(i, j), "0000" & "   "
        If i <= j Then s20 = s20 & Format(theMat(i, j), "0000" & "   " Else s20 = s20 & Format(0, "0000" & "   "
        If i >= j Then s30 = s30 & Format(theMat(i, j), "0000" & "   " Else s30 = s30 & Format(0, "0000" & "   "
    Next j
    s1 = s1 & s10 & vbCr & vbLf
    s2 = s2 & s20 & vbCr & vbLf
    s3 = s3 & s30 & vbCr & vbLf
Next i

MsgBox ("原始值如下:" & vbCrLf & s1 & vbCrLf & "上三角矩阵如下:" & vbCrLf & s2 & vbCrLf & "下三角矩阵为:" & vbCrLf & s3)

End Sub
运行结果如下:
原始值如下:
0001   0002   0003   0004   0005   
0006   0007   0008   0009   0010   
0011   0012   0013   0014   0015   
0016   0017   0018   0019   0020   
0021   0022   0023   0024   0025   

上三角矩阵如下:
0001   0002   0003   0004   0005   
0000   0007   0008   0009   0010   
0000   0000   0013   0014   0015   
0000   0000   0000   0019   0020   
0000   0000   0000   0000   0025   

下三角矩阵为:
0001   0000   0000   0000   0000   
0006   0007   0000   0000   0000   
0011   0012   0013   0000   0000   
0016   0017   0018   0019   0000   
0021   0022   0023   0024   0025
4楼2013-05-25 23:31:22
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ausir

木虫 (正式写手)

稍作修改。 1. theMat的定义只要1 to 5, 1 to 5 就够了。 2. 用Debug.print 可以在即时窗口中显示结果。

Sub Matrix()
Dim theMat(1 To 5, 1 To 5) As Single

Dim s As String, s1 As String, s2 As String, s3 As String, s10 As String, s20 As String, s30 As String

Dim i As Integer, j As Integer

For i = 1 To 5
   For j = 1 To 5
       's = "请输入第" & CStr(i) & "行第" & CStr(j) & "列的数值"
       theMat(i, j) = (i - 1) * 5 + j 'Val(InputBox(s, "")
    Next j
Next i

'MsgBox ("输入完成,按确定后显示输入的阵列。"

s1 = ""
s2 = ""
s3 = ""
For i = 1 To 5
    s10 = ""
    s20 = ""
    s30 = ""
    For j = 1 To 5
        s10 = s10 & Format(theMat(i, j), "0000" & "   "
        If i <= j Then s20 = s20 & Format(theMat(i, j), "0000" & "   " Else s20 = s20 & Format(0, "0000" & "   "
        If i >= j Then s30 = s30 & Format(theMat(i, j), "0000" & "   " Else s30 = s30 & Format(0, "0000" & "   "
    Next j
    s1 = s1 & s10 & vbCr & vbLf
    s2 = s2 & s20 & vbCr & vbLf
    s3 = s3 & s30 & vbCr & vbLf
Next i

s = "原始值如下:" & vbCrLf & s1 & vbCrLf & "上三角矩阵如下:" & vbCrLf & s2 & vbCrLf & "下三角矩阵为:" & vbCrLf & s3

MsgBox (s)
     
Debug.Print s
   
End Sub
5楼2013-05-25 23:34:25
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gyh930912

铁虫 (小有名气)

引用回帖:
5楼: Originally posted by ausir at 2013-05-25 23:34:25
稍作修改。 1. theMat的定义只要1 to 5, 1 to 5 就够了。 2. 用Debug.print 可以在即时窗口中显示结果。

Sub Matrix()
Dim theMat(1 To 5, 1 To 5) As Single

Dim s As String, s1 As String, s2 As String, ...

谢谢!!!
6楼2013-05-27 12:51:30
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