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future_wl木虫 (著名写手)
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[求助]
La掺杂BiFeO3时反铁磁性的设置问题
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我用R3c菱方表示的模型基础上建了2*2*2的超胞,然后用La取代了一个Bi,分子式变成了Bi15LaFe16O48 POSCAR 如下: BiLaFeO3 1.0 11.2735004425 0.0000000000 0.0000000000 5.7346471374 9.7059587077 0.0000000000 5.7346471374 3.2725638144 9.1376124079 O Bi Fe La 48 15 16 1 Direct 0.198650002 0.261649996 0.471150011 0.471150011 0.198650002 0.261649996 0.261649996 0.471150011 0.198650002 0.011650000 0.448650002 0.221149996 0.448650002 0.221149996 0.011650000 0.221149996 0.011650000 0.448650002 0.698650002 0.261649996 0.471150011 0.971149981 0.198650002 0.261649996 0.761650026 0.471150011 0.198650002 0.511650026 0.448650002 0.221149996 0.948650002 0.221149996 0.011650000 0.721149981 0.011650000 0.448650002 0.198650002 0.761650026 0.471150011 0.471150011 0.698650002 0.261649996 0.261649996 0.971149981 0.198650002 0.011650000 0.948650002 0.221149996 0.448650002 0.721149981 0.011650000 0.221149996 0.511650026 0.448650002 0.698650002 0.761650026 0.471150011 0.971149981 0.698650002 0.261649996 0.761650026 0.971149981 0.198650002 0.511650026 0.948650002 0.221149996 0.948650002 0.721149981 0.011650000 0.721149981 0.511650026 0.448650002 0.198650002 0.261649996 0.971149981 0.471150011 0.198650002 0.761650026 0.261649996 0.471150011 0.698650002 0.011650000 0.448650002 0.721149981 0.448650002 0.221149996 0.511650026 0.221149996 0.011650000 0.948650002 0.698650002 0.261649996 0.971149981 0.971149981 0.198650002 0.761650026 0.761650026 0.471150011 0.698650002 0.511650026 0.448650002 0.721149981 0.948650002 0.221149996 0.511650026 0.721149981 0.011650000 0.948650002 0.198650002 0.761650026 0.971149981 0.471150011 0.698650002 0.761650026 0.261649996 0.971149981 0.698650002 0.011650000 0.948650002 0.721149981 0.448650002 0.721149981 0.511650026 0.221149996 0.511650026 0.948650002 0.698650002 0.761650026 0.971149981 0.971149981 0.698650002 0.761650026 0.761650026 0.971149981 0.698650002 0.511650026 0.948650002 0.721149981 0.948650002 0.721149981 0.511650026 0.721149981 0.511650026 0.948650002 0.000000000 0.000000000 0.000000000 0.250000000 0.250000000 0.250000000 0.500000000 0.000000000 0.000000000 0.750000000 0.250000000 0.250000000 0.000000000 0.500000000 0.000000000 0.500000000 0.500000000 0.000000000 0.750000000 0.750000000 0.250000000 0.000000000 0.000000000 0.500000000 0.250000000 0.250000000 0.750000000 0.500000000 0.000000000 0.500000000 0.750000000 0.250000000 0.750000000 0.000000000 0.500000000 0.500000000 0.250000000 0.750000000 0.750000000 0.500000000 0.500000000 0.500000000 0.750000000 0.750000000 0.750000000 0.110600002 0.110600002 0.110600002 0.360599995 0.360599995 0.360599995 0.610599995 0.110600002 0.110600002 0.860599995 0.360599995 0.360599995 0.110600002 0.610599995 0.110600002 0.360599995 0.860599995 0.360599995 0.610599995 0.610599995 0.110600002 0.860599995 0.860599995 0.360599995 0.110600002 0.110600002 0.610599995 0.360599995 0.360599995 0.860599995 0.610599995 0.110600002 0.610599995 0.860599995 0.360599995 0.860599995 0.110600002 0.610599995 0.610599995 0.360599995 0.860599995 0.860599995 0.610599995 0.610599995 0.610599995 0.860599995 0.860599995 0.860599995 0.250000000 0.750000000 0.250000000 请问大家: 1. 在进行计算的时候,这个体系还需要和BiFeO3本征体系一样设置为反铁磁的吗? 2. 如果设置反铁磁,我在INCAR 中设置 MAGMOM= 48*0 15*0 8*-6 8*6 0是否可以,需不需要在POSCAR 中将原子数写为如下形式: O Bi Fe Fe La 48 15 8 8 1 3. POTCAR中Fe的赝势文件,用一个还是两个 期待大家的帮助,谢谢!!! 附上结构优化的INCAR : SYSTEM=BiLaFeO3 ENCUT=800 ISMEAR=0 IBRION=2 ISIF=3 NSW=400 EDIFF=1E-6 EDIFFG=1E-5 EDIFFG=-0.01 ISTART=0 ICHARG=2 ISPIN=2 PREC=A SIGMA=0.1 MAGMOM= 48*0 15*0 8*-6 8*6 0 LREAL=AUTO LWAVE=.FALSE LCHARG=.FALSE |
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4楼2013-05-02 01:41:49
2楼2013-05-01 09:56:11
future_wl
木虫 (著名写手)
- 应助: 87 (初中生)
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3楼2013-05-01 10:13:03
future_wl
木虫 (著名写手)
- 应助: 87 (初中生)
- 金币: 3295.4
- 散金: 1881
- 红花: 5
- 帖子: 1404
- 在线: 676.6小时
- 虫号: 950891
- 注册: 2010-01-30
- 性别: GG
- 专业: 凝聚态物性I:结构、力学和

5楼2013-05-02 08:03:35









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