| 查看: 612 | 回复: 3 | ||
[求助]
VB 分形算法实现科赫格子
|
|
自己写的，加大写A的地方也就是角度的变化不太清楚如何实现？请教高手啊！新虫，金币不多，谅解。 Const pi = 3.14159 Private Sub Form_Click() ScaleTop = 50 ScaleLeft = 0 ScaleWidth = 100 ScaleHeight = -50 Call koch(20, 20, 80, 20, 1) End Sub Sub koch(ax As Single, ay As Single, bx As Single, by As Single, c As Single) Dim cx As Single Dim cy As Single Dim dx As Single Dim dy As Single Dim ex As Single Dim ey As Single Dim fx As Single Dim fy As Single Dim l As Single Dim alpha As Single If (bx - ax) * (bx - ax) + (by - ay) * (by - ay) < c Then Line (ax, ay)-(bx, by) Else cx = ax + (bx - ax) / 3 cy = ay + (by - ay) / 3 ex = bx - (bx - ax) / 3 ey = by - (by - ay) / 3 l = Sqr((ex - cx) * (ex - cx) + (ey - cy) * (ey - cy)) AA”If (ex - cx) > 0 Then AA”alpha = pi / 2 AA”Else AA”alpha = 0 / pi AA” End If dy = cy + Sin(alpha) * l dx = cx + Cos(alpha) * l fx = ex + Cos(alpha) * l fy = ey + Sin(alpha) * l Call koch(ax, ay, cx, cy, c) Call koch(cx, cy, ex, ey, c) Call koch(ex, ey, bx, by, c) Call koch(cx, cy, dx, dy, c) Call koch(dx, dy, fx, fy, c) Call koch(fx, fy, ex, ey, c) End If End Sub  0C99Z%H8}531TL`$N)FUAA6.jpg |
回复此楼» 猜你喜欢
投稿精细化工
已经有6人回复
-
博士读完未来一定会好吗
已经有36人回复
-
之前让一硕士生水了7个发明专利，现在这7个获批发明专利的维护费可从哪儿支出哈？
已经有10人回复
-
博士申请都是内定的吗？
已经有9人回复
-
心脉受损
已经有8人回复
-
读博
已经有5人回复
2楼2013-01-02 10:32:43
|
Const pi = 3.14159 Private Sub Form_Click() ScaleTop = 50 ScaleLeft = 0 ScaleWidth = 100 ScaleHeight = -50 Call koch(5, 0, 20, 20, 80, 20, 1) End Sub Sub koch(n As Integer, s As Integer, ax As Single, ay As Single, bx As Single, by As Single, c As Single) Dim cx As Single Dim cy As Single Dim dx As Single Dim dy As Single Dim ex As Single Dim ey As Single Dim fx As Single Dim fy As Single Dim l As Single Dim alpha As Single If n = 2 Then Line (ax, ay)-(bx, by) Else cx = ax + (bx - ax) / 3 cy = ay + (by - ay) / 3 ex = bx - (bx - ax) / 3 ey = by - (by - ay) / 3 l = Sqr((ex - cx) * (ex - cx) + (ey - cy) * (ey - cy)) If s = 0 Then alpha = pi / 2 ElseIf s = 1 Then alpha = 2 * pi ElseIf s = -1 Then alpha = pi End If dy = cy + Sin(alpha) * l dx = cx + Cos(alpha) * l fx = ex + Cos(alpha) * l fy = ey + Sin(alpha) * l Call koch(n - 1, 0, ax, ay, cx, cy, c) Call koch(n - 1, 1, cx, cy, dx, dy, c) Call koch(n - 1, 0, dx, dy, fx, fy, c) Call koch(n - 1, -1, fx, fy, ex, ey, c) Call koch(n - 1, 0, ex, ey, bx, by, c) Call koch(n - 1, 2, cx, cy, ex, ey, c) End If End Sub 迭代次数为一时正确，但是大于1就有问题了 |
3楼2013-01-04 13:24:16
4楼2013-01-04 13:24:51