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[ÇóÖú] ÐÂÒ©Ñз¢ÖÐÆÀ¹ÀС·Ö×Ó»¯ºÏÎKÐÔµÄLog PÊèË®³£ÊýµÄÒâÒåÊÇʲô£¿

×î½üÎÒÃǺϳɳöÀ´Ò»Öл¯ºÏÎïB£¬ÊèË®³£ÊýLog P=3.21£¬ ÆäĸÌ廯ºÏÎïAµÄLog P=-1.51¡£µ«ÊÇ£¬Ïà¶ÔÓÚĸÌ廯ºÏÎïA£¬ÎÒÃǵϝºÏÎïB±íÏÖ³ö¸ü¼ÓÇ¿ÁÒµÄÓÕµ¼Ï¸°ûµòÍöµÄÄÜÁ¦¡£ÎÒÏëÖªµÀÕâÁ½¸öÊýÖµÔÚÆÀ¹ÀÎÒµÄл¯ºÏÎïµÄ¼ÛÖµ·½Ã棬´ú±íʲôÒâÒ壿Èç¹û˵ÊýÖµÔ½´ó£¬´ú±íÊèË®ÐÔԽǿ£¬ÎÒÏëÁ˽âÒ»ÏÂÒ»°ãÐÂÒ©¿ª·¢¹ý³ÌÖÐÕâ¸öÊýÖµÔÊÐíµÄµÄ³ß¶ÈÓжà´óÄØ£¿»òÕßÇ×°®µÄ³æÓÑÃǸøÎÒÌṩһЩ×ÊÁÏ£¬ÎÒ×Ô¼ºÑ§Ï°Ò»Ï£¡ÏÈлл´ó¼ÒÁË£¡
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»ØÌûÖö¥ ( ¹²ÓÐ2¸ö )

catwithdog

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¡ï ¡ï ¡ï ¡ï ¡ï ¡ï ¡ï
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marktiger: ½ð±Ò+2, »¶Ó­²ÎÓ룬»¶Ó­³£À´¡£ 2012-11-28 08:34:52
sonny: ½ð±Ò+5, ¡ï¡ï¡ï¡ï¡ï×î¼Ñ´ð°¸ 2012-11-28 11:20:53
sonny: »ØÌûÖö¥ 2012-11-28 11:21:08
For your reference:

1.        ÎÒÏëÁ˽âÒ»ÏÂÒ»°ãÐÂÒ©¿ª·¢¹ý³ÌÖÐÕâ¸öÊýÖµÔÊÐíµÄµÄ³ß¶ÈÓжà´óÄØ£¿
Based on Lipinski's Rule of Five,  log P in −0.4 to +5.6 range will be ideal drug. So your compounds are good.
2.        ÎÒÏëÖªµÀÕâÁ½¸öÊýÖµÔÚÆÀ¹ÀÎÒµÄл¯ºÏÎïµÄ¼ÛÖµ·½Ã棬
First, you need understand what is Log P. LogP , partition (P) coefficient , is the ratio of concentrations of a compound in a mixture of two immiscible phases at equilibrium. These coefficients are a measure of the difference in solubility of the compound in these two phases. Normally one of the solvents chosen is water while the second is hydrophobic such as octanol. Hence both the partition and distribution coefficient are measures of how hydrophilic ("water-loving" or hydrophobic ("water-fearing" a chemical substance is.
Log P = log (compound in Octanol/ compound in water)

So, ĸÌ廯ºÏÎïAµÄLog P=-1.51,  is less  hydrophobic than »¯ºÏÎïB£¬ Log P=3.21. In another word, »¯ºÏÎïBÊèË®ÐÔÇ¿.

3.        ´ú±íʲôÒâÒ壿
In medical practice, partition coefficients are useful for example in estimating distribution of drugs within the body. Hydrophobic drugs with high octanol/water partition coefficients are preferentially distributed to hydrophobic compartments such as lipid bilayers of cells while hydrophilic drugs (low octanol/water partition coefficients) preferentially are found in hydrophilic compartments such as blood serum.
So »¯ºÏÎïB may have more distribution in lipid bilayers of cells which may be your target place. (that's only we guess)
4Â¥2012-11-28 03:28:20
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cpujacs

ÈÙÓþ°æÖ÷ (ÖªÃû×÷¼Ò)

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¡ï
marktiger: ½ð±Ò+1, »¶Ó­²ÎÓ룬»¶Ó­³£À´¡£ 2012-11-28 08:35:10
sonny: »ØÌûÖö¥ 2012-11-28 11:21:00
ÒýÓûØÌû:
4Â¥: Originally posted by catwithdog at 2012-11-28 03:28:20
For your reference:

1.        ÎÒÏëÁ˽âÒ»ÏÂÒ»°ãÐÂÒ©¿ª·¢¹ý³ÌÖÐÕâ¸öÊýÖµÔÊÐíµÄµÄ³ß¶ÈÓжà´óÄØ£¿
Based on Lipinski's Rule of Five,  log P in −0.4 to +5.6 range will be ideal drug. So your compounds are  ...

The logP value of a compound, which is the logarithm of its partition coefficient between n-octanol and water log(coctanol/cwater), is a well established measure of the compound's hydrophilicity. Low hydrophilicities and therefore high logP values cause poor absorption or permeation. It has been shown for compounds to have a reasonable propability of being well absorbt their logP value must not be greater than 5.0. The distribution of calculated logP values of more than 3000 drugs on the market underlines this fact (see diagram)

cLogPDis.gif

5Â¥2012-11-28 08:27:09
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heyongyao

½ð³æ (ÕýʽдÊÖ)

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¡ï ¡ï ¡ï
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marktiger: ½ð±Ò+1, »¶Ó­²ÎÓ룬»¶Ó­³£À´¡£ 2012-11-28 08:34:25
sonny: ½ð±Ò+2 2012-11-28 11:18:44
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2Â¥2012-11-28 00:23:04
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heyongyao

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¡ï ¡ï ¡ï
marktiger: ½ð±Ò+1, »¶Ó­²ÎÓ룬»¶Ó­³£À´¡£ 2012-11-28 08:34:31
sonny: ½ð±Ò+2 2012-11-28 11:18:50
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3Â¥2012-11-28 00:24:24
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yiwenbin

½û³æ (ÕýʽдÊÖ)

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marktiger: ½ð±Ò+1, »¶Ó­²ÎÓ룬»¶Ó­³£À´¡£Ï´οÉÒÔÑ¡ÔñÓ¦Öú»ØÌû¹þ¡£ 2012-11-29 08:15:06
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6Â¥2012-11-28 08:45:16
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yylex

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sonny: ½ð±Ò+1 2012-11-28 11:22:36
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7Â¥2012-11-28 09:10:21
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sonny

½ð³æ (ÖøÃûдÊÖ)

ÒýÓûØÌû:
4Â¥: Originally posted by catwithdog at 2012-11-28 03:28:20
For your reference:

1.        ÎÒÏëÁ˽âÒ»ÏÂÒ»°ãÐÂÒ©¿ª·¢¹ý³ÌÖÐÕâ¸öÊýÖµÔÊÐíµÄµÄ³ß¶ÈÓжà´óÄØ£¿
Based on Lipinski's Rule of Five,  log P in −0.4 to +5.6 range will be ideal drug. So your compounds are  ...

ÄÇÎÒÊÇ·ñ¿ÉÒÔÀí½âÎÒ»¯ºÏÎïB¸üÈÝÒ×½øÈëϸ°ûÀ´·¢»ÓÒ©Ð§ÄØ£¿
ÕâλÈÊÐֵĽâÊͺÜÈ«Ãæ£¬Äܹ»¸øÎÒÌṩһЩÏà¹ØµÄÎÄÏ×ÄØ£¿ÎÒÏëºÃºÃ¿´Ò»Ï£¬»òÕßÒýÓÃÒ»ÏÂÔÙÎÄÕÂÖУ¿Ð»Ð»ÁË£¡
8Â¥2012-11-28 11:34:29
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catwithdog

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ÄÇÎÒÊÇ·ñ¿ÉÒÔÀí½âÎÒ»¯ºÏÎïB¸üÈÝÒ×½øÈëϸ°ûÀ´·¢»ÓÒ©Ð§ÄØ£¿
Theoretically you can explain it in this way for your paper.

ÕâλÈÊÐֵĽâÊͺÜÈ«Ãæ£¬Äܹ»¸øÎÒÌṩһЩÏà¹ØµÄÎÄÏ×ÄØ£¿ÎÒÏëºÃºÃ¿´Ò»Ï£¬»òÕßÒýÓÃÒ»ÏÂÔÙÎÄÕÂÖУ¿Ð»Ð»ÁË£¡
Sorry, I don¡¯t have this reference on hand now.
9Â¥2012-11-29 04:55:00
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