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GGhigh

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1280 CO=0;T=0;M=0;V=1;CH=1;AC=0.001;  %function evaluation;
1290 BA=C(M+1);
1300 K2=WW*WW-BA*BA;
1310 SS=sign(K2);
1320 if SS=1 and abs(K2)>0.01 then K=sqrt(K2)
1330 if  SS=-1 and abs(K2)>0.01 then K=sqrt(-K2)
1340 if SS=0 or abs(K2)<=0.01
1350 X=WW/R ; MM=1;   gosub 2220          %ÕâÀﻹδµ÷ÊÔ
1360 Y1=J1;Y2=J2;Y3=J3;Y4=J4;
1370 X=K;MM=SS;gosub 2220
1380 Z1=J1;Z2=J2;Z3=J3;Z4=J4;
1390 X=WW;MM=1;gosub 2220
1400 SN=J2*Y3-Y1*J4;
1410 SD=J1*Y3-Y1*J3;
1420 S=WW*SN/SD;
1430 FT=K*Z2/Z1;
1440 M=M+1;
1450 F(M)=K*K2*SN*Z1*Z2/WW-K^2*Z2^2*SD
1460 F(M)=F(M)+N^2*BA^2*Z1^2*SD/(WW*WW);
1470 if V==1 goto 1500
1480 if M>=2 goto 1660
1490 goto 1290
1500  BA=BA+0.02*CH;
1510  if BA>=WW then BA=BA-0.01;CH=-1;
1520  if M=1 GOTO 1300
1530 SS==sign(F(M));ST==sign(F(M-1));
1540 if SS==ST then F(M-1)=F(M);M=M-1;GOTO 1300
1550 C(1)=BA-0.005*CH;
1560  C(2)=BA-0.01*CH;
1570 V=0;T=T+1;M=0
1580 GOTO 1290
........
1660
...(1660ÊÇÁíÍâÒ»¸ö×Ó³ÌÐòÁË£©
ÎÒ¸ÄдµÄmatlab³ÌÐòÈçÏ£º
CO=0;T=0;M=0;V=1;CH=1;AC=0.001;  %function evaluation;
BA=C(M+1);
K2=WW*WW-BA*BA;
SS=sign(K2);
if (SS==1 & abs(K2)>0.01)
    K=sqrt(K2);
end
if  (SS==-1 & abs(K2)>0.01)
    K=sqrt(-K2);
end
if (SS==0 | abs(K2)<=0.01)
    CO=CO+1;   %ÐÞÕýMODIFICATION£»£¨ÕâÊÇ2040£©
    if CO>2
        disp ('error')
        return
    else  disp('MODIFICATION')
        BA=BA-0.002;
        return
    end
end
X=WW/R ; MM=1;            
bessel;   £¨ÕâÀï¾ÍÊÇ×Ó³ÌÐò2220£©
Y1=J1;Y2=J2;Y3=J3;Y4=J4;
X=K;MM=SS;
bessel;
Z1=J1;Z2=J2;Z3=J3;Z4=J4;
X=WW;MM=1;
bessel;
SN=J2*Y3-Y1*J4;
SD=J1*Y3-Y1*J3;
S=WW*SN/SD;
FT=K*Z2/Z1;
M=M+1;
F(M)=K*K2*SN*Z1*Z2/WW-K^2*Z2^2*SD;%ÓÐÎÊÌâ
F(M)=F(M)+N^2*BA^2*Z1^2*SD/(WW*WW);
if V==1
    BA=BA+0.02*CH;
    if BA>=WW
        BA=BA-0.01;CH=-1;
    end
    if M==1
       return
    else
        SS==sign(F(M));ST==sign(F(M-1));
        if SS==ST
            F(M-1)=F(M);
            M=M-1;
            return
        else C(1)=BA-0.005*CH;
             C(2)=BA-0.01*CH;
             V=0;T=T+1;M=0;
            return
        end
    end
end
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GGhigh

Òø³æ (СÓÐÃûÆø)

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In an assignment  A(I) = B, the number of elements in B and
I must be the same.
2Â¥2012-09-06 17:47:19
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libralibra

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jjdg: ½ð±Ò+1, ¸ÐлÌṩ½¨Òé 2012-09-06 21:22:53
GGhigh: ½ð±Ò+10, ¡ï¡ï¡ïºÜÓаïÖú 2012-09-07 09:51:00
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gotoÇ°Ãæ³öÏֵıêºÅ¸Ä³Éloop,ÖмäµÄif...goto ºóÃæµÄ±êºÅ ¸ÄΪѭ»·ÖÕÖ¹µÄbreakÌõ¼þ
M=M+1;¿ÉÄÜMÊÇϱê,×Ô¼Ó,
matlabÓÐwhileÑ­»·,¿ÉÒÔÓÃËÀÑ­»·while 1
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In an assignment  A(I) = B, the number of elements in B and I must be the same.
ÊÇ˵: ÓÃA(I)=BÀ´½«ÏòÁ¿/¾ØÕóAµÄϱêI±íʾµÄÔªËØÕûÌåÌæ»»ÎªÏòÁ¿/¾ØÕóBʱ,BµÄÔªËØ¸öÊý±ØÐëÓëϱêIµÄ³¤¶ÈÏàµÈ.
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matlab/VB/python/c++/Javaд³ÌÐòÇë·¢QQÓʼþ:790404545@qq.com
3Â¥2012-09-06 20:06:37
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GGhigh

Òø³æ (СÓÐÃûÆø)

ÒýÓûØÌû:
3Â¥: Originally posted by libralibra at 2012-09-06 20:06:37
°Ñgosub¸Ä³Éµ÷ÓÃ×Óº¯Êý,ËùÓÐÓõ½µÄ²ÎÊýÓú¯Êý¶¨ÒåÀ´´«µÝ
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M=M+1;¿ÉÄÜMÊÇϱê,×Ô¼Ó,
matlabÓÐwhileÑ­»·,¿ÉÒÔÓÃËÀÑ­»·while 1
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