| 查看: 1570 | 回复: 10 | |||
| 本帖产生 1 个 翻译EPI ，点击这里进行查看 | |||
| 当前只显示满足指定条件的回帖，点击这里查看本话题的所有回帖 | |||
yearover银虫 (正式写手)
|
[求助]
一个偏于数学上的翻译，请求指正
|
||
|
a. The PWE method converges to the true value downward with the increasing of the numbers of plane waves. One hundred plane waves are needed to guarantee the relative error less than 1.0%. PWE方法随着the numbers of plane waves的增加，向下收敛接近到精确解。100个plane waves可以保证相对误差小于1%。 b. Results show that a very low convergence happens with the large n due to the well-known Gibbs oscillations at the interfaces while the computational time is increasing quickly. The reason is that the order of matrix in Eq. (11) is 4n+2, which leads to a large amount of matrix operation with a growth of power series manner. 当n值很大时，收敛速度变慢，其原因是Gibbs oscillations at the interfaces ；同时需要大量的计算时间。原因是方程11中的矩阵的阶数为4n+1，因此，随着n的增大，矩阵计算过程（步骤）呈幂级数级增长。 如有不足之处请指教，谢谢 |
回复此楼» 猜你喜欢
售SCI一区T0P文章，我:8O.55.1.O.5.4,科目齐全,可+急
已经有3人回复
-
售SCI文章，我:8O5.5.1.O.54,科目齐全,可+急
已经有3人回复
-
售SCI一区文章，我:8.O.551.O.5.4,科目全,可伽急
已经有3人回复
-
售SCI文章，我:8O5.5.1.O.54,科目齐全,可+急
已经有3人回复
-
售SCI-T0P文章，我:8O.5.5.1.O.54,科目齐全,可+急
已经有6人回复
-
售一区SCI文章T0P，我:8O.551.O54,科目全,可十急
已经有9人回复
-
售SCI-T0P文章，我:8O.5.5.1.O.54,科目齐全,可+急
已经有3人回复
-
考博求助
已经有3人回复
-
售SCI一区文章，我:8.O.551.O.5.4,科目全,可伽急
已经有5人回复
-
售SCI一区T0P文章，我:8.O.55.1.O.5.4,科目全,可+急
已经有4人回复
8814402
至尊木虫 (职业作家)
- 翻译EPI: 509
- 应助: 18 (小学生)
- 贵宾: 0.381
- 金币: 12921.1
- 散金: 47
- 红花: 16
- 帖子: 4185
- 在线: 357.9小时
- 虫号: 1184404
- 注册: 2011-01-06
- 专业: 药物学其他科学问题
【答案】应助回帖
★ ★ ★ ★ ★ ★
爱与雨下: 金币+1 2012-05-29 19:36:53
yearover: 金币+5, 翻译EPI+1, ★有帮助, 谢谢，不过我把表达的意思说错了，应该是按照中文写的英文，请看英文写法是否正确。 2012-05-29 22:54:19
爱与雨下: 金币+1 2012-05-29 19:36:53
yearover: 金币+5, 翻译EPI+1, ★有帮助, 谢谢，不过我把表达的意思说错了，应该是按照中文写的英文，请看英文写法是否正确。 2012-05-29 22:54:19
|
a. The PWE method converges to the true value downward with the increasing of the numbers of plane waves. One hundred plane waves are needed to guarantee the relative error less than 1.0%. 随着平面波数量的增加， PWE方法向下收敛接近到精确解。为保证相对误差小于1%，需要100个平面波。 b. Results show that a very low convergence happens with the large n due to the well-known Gibbs oscillations at the interfaces while the computational time is increasing quickly. The reason is that the order of matrix in Eq. (11) is 4n+2, which leads to a large amount of matrix operation with a growth of power series manner. 结果显示，当n值很大时，收敛速度变慢，其原因是众所周知的界面Gibbs振动，而同时需要的计算时间快速增加。原因是方程11中的矩阵的阶数为4n+1，造成大量的矩阵计算过程（步骤）呈幂级数增长。 |
3楼2012-05-29 17:41:11
jiujian1984
金虫 (正式写手)
- 应助: 35 (小学生)
- 金币: 1320
- 帖子: 515
- 在线: 25.3小时
- 虫号: 1465240
- 注册: 2011-10-28
- 性别: GG
- 专业: 植物化学保护
2楼2012-05-29 12:43:54
aixiaoxi123
铁虫 (初入文坛)
- 应助: 0 (幼儿园)
- 金币: 603.5
- 散金: 43
- 帖子: 47
- 在线: 32.3小时
- 虫号: 1799041
- 注册: 2012-05-06
- 专业: 环境工程
4楼2012-05-29 21:16:15
yearover
银虫 (正式写手)
- 应助: 1 (幼儿园)
- 金币: 2145.9
- 散金: 231
- 帖子: 412
- 在线: 202小时
- 虫号: 438395
- 注册: 2007-09-21
- 性别: GG
- 专业: 水工结构和材料及施工
yearover: 回帖置顶 2012-05-29 22:55:58
yearover: 取消置顶 2012-05-29 23:02:18
yearover: 取消置顶 2012-05-29 23:02:18
|
我把意思表达错了，应该是根据中文翻译成英文，请大家看看英文的表达是否有问题。 a. The PWE method converges to the true value downward with the increasing of the numbers of plane waves. One hundred plane waves are needed to guarantee the relative error less than 1.0%. PWE方法随着the numbers of plane waves的增加，向下收敛接近到精确解。100个plane waves可以保证相对误差小于1%。 b. Results show that a very low convergence happens with the large n due to the well-known Gibbs oscillations at the interfaces while the computational time is increasing quickly. The reason is that the order of matrix in Eq. (11) is 4n+2, which leads to a large amount of matrix operation with a growth of power series manner. |
5楼2012-05-29 22:55:47
