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dengwei_19

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[求助] 现在做到高斯函数的误差函数一步,又是一个方程不知道用matlab怎么写

求w,求详解!谢谢!!!
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dbb627

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【答案】应助回帖

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dengwei_19: 金币+4, ★★★★★最佳答案 2012-04-13 14:49:55
dengwei_19: 回帖置顶 2012-04-13 15:17:11
引用回帖:
6楼: Originally posted by dengwei_19 at 2012-04-13 14:39:24:
x =

   81.4787

这个是解出来的w吗?

是的,这个就是matlab求出的数值解,做图也可以看出来在80附近。
The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
7楼2012-04-13 14:43:37
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onesupeng

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感谢参与,应助指数 +1
这个matlab有点悬吧?我觉得自己编程序算恐怕更好呢
长期招收博士生,参见http://fsl-unsw.com
2楼2012-04-13 13:47:46
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dengwei_19

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铁齿金不换诚实可靠小郎君

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2楼: Originally posted by onesupeng at 2012-04-13 13:47:46:
这个matlab有点悬吧?我觉得自己编程序算恐怕更好呢

不会吧。。。。。没办法求吗?
3楼2012-04-13 13:53:05
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dbb627

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感谢参与,应助指数 +1
dengwei_19: 金币+6, ★★★很有帮助 2012-04-13 14:36:22
dengwei_19: 回帖置顶 2012-04-13 15:40:01
>> syms x
>> syms w;int(exp(-x^2),0,w)

ans =

(pi^(1/2)*erf(w))/2

>> syms w;int(exp(-x^2),0,-w)

ans =

-(pi^(1/2)*erf(w))/2
===========
>> fun=@(x)-5.4*(pi^(1/2)*erf(10*2^0.5./x))/2-2.8*(pi^(1/2)*erf(40*2^0.5./x))/2+2.6;
>> x=0.1:0.1:100;
>> y=feval(fun,x);
>> plot(x,y)
>> [x,feval,flag]=fsolve(fun,80)

Equation solved.

fsolve completed because the vector of function values is near zero
as measured by the default value of the function tolerance, and
the problem appears regular as measured by the gradient.




x =

   81.4787


feval =

-9.0775e-010


flag =

     1

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The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
4楼2012-04-13 14:19:25
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