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落月随风

铜虫 (小有名气)

[求助] 紧急求助duffing算子的幅频分岔曲线及整个方程的分岔图matlab代码

求duffing算子的幅频分岔曲线及整个方程的分岔图matlab代码,如有不甚感激!!
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zzqmessi

新虫 (初入文坛)

请问 你的幅频响应曲线做出来了吗 求代码 谢谢
4楼2014-04-10 15:55:14
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dbb627

荣誉版主 (著名写手)

【答案】应助回帖

★ ★ ★ ★ ★ ★ ★ ★ ★ ★
感谢参与,应助指数 +1
落月随风: 金币+10, ★★★很有帮助, 我想要分岔过度到混沌的图,不过还是感谢 2012-04-12 21:59:45
以前帮别人写的代码,不知是否你想要的
拷到editor中保存为.m文件,点击run运行
倍周期分岔图
CODE:
function AA

global mu w F;
mu=0.3;w=1.2;
cF=[0.20 0.27 0.289 0.293 0.32 0.35 0.37 0.4 0.65 0.7];
k=0;
for F=cF
    k=k+1;
[t,x]=ode45(@duffing,[0,2000],[2,0.01]);
x1=x(:,1);
count=find(t>1800);
Y=x1(count,:);
t1=t(count,:);
subplot(5,2,k)
plot(t1,Y)
xlabel('t');
ylabel('x ');
s=['t=0 x=2 y=0.01 F=',num2str(F)];
title(s);
end

function dx=duffing(t,x)
global mu w F;
dx=[x(2);F*cos(w*t)-mu*x(2)+x(1)-x(1).^3];

杜芬(Duffing)方程 Poincare 截面图
CODE:
function aa
global mu w F;
mu=0.05;w=1;
F=7.5;
x0=[1;0.2];
tspan = 0:0.1*2*pi:50000;
[t,y]=ode45(@duffing,tspan,x0);
m=zeros(7000,1);
n=zeros(7000,1);
for i=1:7000
    m(i,1)=y(10*i,1);
    n(i,1)=y(10*i,2);
end
plot(m,n,'k.','markersize',1);

function dx=duffing(t,x)
global mu w F;
dx=[x(2);F*cos(w*t)-mu*x(2)-x(1).^3];

[ Last edited by dbb627 on 2012-4-11 at 15:49 ]
The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
2楼2012-04-11 15:43:29
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dbb627

荣誉版主 (著名写手)

【答案】应助回帖

结果如图所示





The more you learn, the more you know, the more you know, and the more you forget. The more you forget, the less you know. So why bother to learn.
3楼2012-04-11 15:44:56
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