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ÓàÔó³É(½ð±Ò+2): лл²ÎÓëÓ¦Öú£¡ 2012-02-25 04:30:16
cotan = 1/tan ÊÇÂð£¿
CODE:
program ganeiliwucha
implicit none
External FS
Integer I,L,N
Dimension X(2),Y(2),C(2)
Double Precision X, Y, EPS,C
Data X/0.00,0.01/
open (2000, file='test.dat', status='unknown' )
EPS=1.0D-06
CALL DSNSE(2,EPS, X, Y, FS, L)
write(*,*) L
IF(L.GT.0)then
C(1)=cos(X(2))/sin(X(1)+X(2))*tan(20.0/180*3.14)-1.0 ! AC¸ËµÄÄÚÁ¦Îó²î
C(2)=cos(X(1))/sin(X(1)+X(2))*sin(20.0/180*3.14)-1.0 ! BC¸ËµÄÄÚÁ¦Îó²î
do I=1,2
write(2000,*) X(I)
end do
end IF
close(2000)
end
SUBROUTINE DSNSE(N,EPS,X,Y,FS,L)
DIMENSION X(N),Y(N)
DOUBLE PRECISION X,Y,F,D,S,EPS
L=500
5 CALL FS(X,N,F,Y)
IF (F.GE.EPS) THEN
L=L-1
IF (L.EQ.0) RETURN
D=0.0
DO 20 J=1,N
20 D=D+Y(J)*Y(J)
IF (D+1.0.EQ.1.0) THEN
L=-1
RETURN
END IF
S=F/D
DO 30 I=1,N
30 X(I)=X(I)-S*Y(I)
GOTO 5
END IF
RETURN
END
SUBROUTINE FS(X, N, F, Y)
DIMENSION X(N), Y(N)
Double precision X,Y,F,F1,F2,DF1,DF2,A,B,K
A=20.0/180*3.14
K=0.5
F1=X(1)+X(2)-cos(A)
F2=sin(X(1))*cos(A)*(1+K/tan(A))+SIN(X(2))*(1.0-K/sin(A))-cos(A)
F=F1*F1+F2*F2
DF1=1.0
DF2=cos(X(1))*cos(A)*(1+K/tan(A))
Y(1)=2.0*(F1*DF1+F2*DF2)
DF1=1.0
DF2=COS(X(2))*(1.0-K/sin(A))
Y(2)=2.0*(F1*DF1+F2*DF2)
RETURN
END
test.dat ÖÐÓнá¹ûÁË
0.52845823638034783
0.41064723658717200
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11Â¥
2012-02-23 20:01:58
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×¢²á: 2006-02-13
רҵ: ÎÛȾÉú̬»¯Ñ§
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ºì»¨: 4
Ìû×Ó: 1124
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×¢²á: 2005-03-17
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12Â¥
:
Originally posted by
snoopyzhao
at 2012-02-23 20:03:15:
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