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liuhuichina

银虫 (正式写手)

[求助] 一道物化题

某一元酸HA在298K,浓度为0.01时的离解度为0.0810,应用德拜-休克尔公式计算离子的平均活度系数及该一元酸的真正离解常数Ka。已知A=0.509(mol۰kg-1)1/2
说明:A的式中“-1”和“1/2”是上标
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狗子哥哥

铁虫 (正式写手)

【答案】应助回帖

感谢参与,应助指数 +1
liuhuichina(金币+15): 2011-12-19 16:23:11
根据解离度计算出HA和A-的平衡浓度。如果不考虑水的电离的话H+的浓度也应该等于A-的浓度,然后算出离子强度,算出平均活度系数,分别算出活度,最后用活度代替浓度算出Ka
2楼2011-12-17 21:46:45
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changyf

铁杆木虫 (职业作家)

【答案】应助回帖

感谢参与,应助指数 +1
liuhuichina(金币+15): 2011-12-19 16:23:18
先用浓度和解离度算出氢离子及A离子的浓度,再利用休克尔公式算出平均活度系数,再分别算出氢离子和A离子及HA的活度,解离常数K等于氢离子活度乘以A离子活度除以HA的活度。
3楼2011-12-17 22:47:23
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