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hmily601木虫 (正式写手)
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[求助]
高手翻译下这几句话吧,谢谢！！！
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| 经查阅相关参考文献，当只有一个鼠李糖基直接连在山奈酚的C-7或C-3位时，鼠李糖基的端头氢信号化学位移约为5.2 ppm，根据化合物1的糖基端头氢化学位移值及偶合常数，确定两个鼠李糖基不可能直接连在山奈酚母体的C-7和C-3位，那就只有半乳糖直接连在山奈酚母体的C-7和C-3位上。在化合物1的碳谱上，6个糖基的端头碳信号在化学位移100.1，100.7 ppm这两处有重叠，糖基的C-2，C-3，C-4，C-5这四个位置的碳化学位移都集中分布在68.2-76.4 ppm，且在68.2-71.9 ppm出现严重重叠，鼠李糖上的甲基碳信号化学位移也非常相近（17.7ppm和17.9ppm）。因此，根据这六个糖基碳的化学位移分布情况及重叠情况，说明山奈酚母体C-7和C-3位上的糖链化学环境非常相像，经过参考相关文献[13-15]，确定山奈酚母体上C-7和C-3位所连的糖链是相同的，糖链结构为-半乳糖-半乳糖-鼠李糖。 |
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terry_well
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爱与雨下(金币+2): 2011-12-12 08:35:01
hmily601(金币+100, 翻译EPI+1): 辛苦了啊！！！呵呵 2011-12-12 22:12:07
爱与雨下(金币+2): 2011-12-12 08:35:01
hmily601(金币+100, 翻译EPI+1): 辛苦了啊！！！呵呵 2011-12-12 22:12:07
After checking the relevant references, when only one rhamnose base directly connected at the position of C-7 or C-3 in kaempferol molecule, the first hydrogen-based signal chemical shift for rhamnose was about 5.2 ppm. We could determine the two rhamnose base which can not be directly connected at the position of C-7 and C-3 in the mother of kaempferol according to the first hydrogen of sugar-based groups chemical shift values and coupling constants of the compound 1. Instead, it can only be directly connected at the position of C-7 and C-3 in galactose mother kaempferol. For C-NMR spectra of compound 1, there was two overlap for the chemical shift signal (100.1 and 100.7 ppm) for the ends carbon of the six glycosylation. In addition, the carbon chemical shifts at four positions of C-2, C-3, C-4, C-5 sugar-based groups are concentrated in the 68.2-76.4 ppm, and there was a severe overlap in the range of 68.2-71.9 ppm. Besides, the chemical shifts signal for methyl carbon of rhamnose is also very similar which are 17.7ppm and 17.9ppm. Thus, according to the condition of their chemical shift distribution and overlap for the six carbons in sugar-based groups, it was indicated that C-7 and C-3 position in kaempferol parent on the sugar chain was in a very similar chemical environment. It was further determined through the relevant literature [13-15] that the sugar chains connected at C-7 and C-3 bits of kaempferol parent are identical and the structure of such sugar chain should be galactose-galactose-rhamnose. 终于搞完了，都晕菜了。 |
2楼2011-12-12 01:02:53
