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hmily601木虫 (正式写手)
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[求助]
英语高手帮忙翻下这几句话 谢谢！！！
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根据黄酮类化合物O-糖苷中苷元的苷化位移规律。 根据文献[3]，当糖上的羟基甙化时将使该-OH所在碳原子产生低场位移，半乳糖的C-6化学位移在成甙前约为62.0ppm，在化合物1的碳谱中，化学位移65.4，66.9，68.0，69.9处有四处碳信号，信号明显处于低场，比半乳糖的C-6化学位移成甙前向低场位移了+4~+6个单位，应该对应的是四个半乳糖的C-6信号，根据以上分析，确定四个半乳糖的C-6位都成了糖甙。 |
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terry_well
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hmily601(金币+50, 翻译EPI+1): 谢谢 辛苦你喽！！ 2011-12-12 00:13:29
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According to the law of displacement for flavonoid O-glycoside daidzein glycosides… According to the literature [3], the glycosides for hydroxyl of sugar occur will induce a low-field shift for the carbon atoms connected to –OH groups and the chemical shifts for C-6 of galactose was about 62.0ppm before glycoside. Based on the 12C-NMR of compound 1, it was shown that there were four chemical shifts namely 65.4, 66.9, 68.0 and 69.9 ppm. Such signal mentioned above was obviously in the low-field, which was changed to low-field by +4 to +6 units compared with the C-6 chemical shifts for galactose before glycosides. This might correspond to the signal of a 4.5 galactose C-6. According to the above analysis, it was confirmed that C-6 bits of 4.5 galactose had changed into glycosides. 今天有空，给你都翻译了。 |
2楼2011-12-12 00:00:44
hmily601
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3楼2011-12-12 00:18:54
