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【答案】应助回帖
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爱与雨下(金币+2): ~! 2011-09-17 19:24:10
sltmac(金币+2, 翻译EPI+1): 感谢应助，欢迎常来~ 2011-09-19 10:17:08
Micro-dilution method. This method has been adopted from NCCLS M26-T (Food and Drug Administration, 1991); (National Committee for Clinical Laboratory Standards, 1999), with modification.微量稀释法 这个方法采自NCCLS M26-T。并做了些修改。（此处不明白为啥会是FDA的参考文献，都已经说了是NCCLS了）
In short: 100 µl antibiotic solutions were pipetted into micro-titer plates by twofold dilutions. 100 µl freshly grown bacteria were added to the wells in a density of 2.5·105 CFU (final concentration per well). 简言之，100微升的抗生素溶液按双倍稀释原则，吸入至微量皿中。100微升新鲜生长的细菌按密度为2.5X10e5CFU(每孔终浓度）加入孔中。
Micro-titer plates were incubated overnight (≙ MBC/L) or 4 h (≙ MBC/S). CFU was determined by diluting each well in tenfold dilutions.微量皿过夜培养或者孵育4个小时。集落形成单位通过10倍稀释法测量。（搞不清括号里的是啥）
From each dilution, aliquots were transferred on agar plates and incubated overnight. On the following day, the number of colonies was evaluated and the initial CFU/well retrospectively calculated.
每次稀释，转移等倍体积液体至琼脂平板并过夜培养。第二天，细菌克隆数即可被估计，并且起始每孔CFU也可回顾性计算到。
整理版：
微量稀释法 这个方法采自NCCLS M26-T。并做了些修改。简言之，100微升的抗生素溶液按双倍稀释原则，吸入至微量皿中。100微升新鲜生长的细菌按密度为2.5X10e5CFU(每孔终浓度）加入孔中。微量皿过夜培养或者孵育4个小时。集落形成单位通过10倍稀释法测量。每次稀释，转移等倍体积液体至琼脂平板并过夜培养。第二天，细菌克隆数即可被估计，并且起始每孔CFU也可回顾性地计算到。 |
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