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引用回帖:
Originally posted by saheya at 2011-07-17 17:33:24:
原问题的第一种做法也是正确的,连续函数的极限直接带入即可;
对于等价无穷小的想减需要谨慎,必须体现他俩个的差才可以,一般都用泰勒公式展开计算是最方便的;
希望对你有帮助!

谢谢!
11楼2011-07-17 18:27:52
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