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joansky

金虫 (小有名气)

[求助] 请教一个while loop的问题

下面两个while loop的小程序,第二个比第一个多了一行,在跳出while loop后为什么会output n=4的值?

main ( ) {
        int n = 0;
       
        while (n++<3)  
                printf("n is %d\n", n);               
       
        printf("That's all this program does.\n";
}

OUTPUT:
n is 1
n is 2
n is 3
That's all this program does.

----------------------------------------------------------------------------------------

main ( ) {
        int n = 0;
       
        while (n++<3)  
                printf("n is %d\n", n);               
        printf("n is %d\n", n);
        printf("That's all this program does.\n";
}

OUTPUT:
n is 1
n is 2
n is 3
n is 4
That's all this program does.
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mengxc

木虫 (著名写手)

★ ★
xzhdty(金币+2): 有你回更精彩 2011-06-07 16:51:47
引用回帖:
Originally posted by joansky at 2011-06-07 11:16:55:
谢谢你

6楼2011-06-07 11:46:40
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mengxc

木虫 (著名写手)

【答案】应助回帖

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jjdg(金币+2): 感谢参与 2011-06-07 15:09:01
第二个printf("n is %d\n", n);已经是在WHILE循环外边了,循环在n=3输出后,又n++,变成4,不满足n++<3,跳出循环
2楼2011-06-07 08:38:30
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joansky

金虫 (小有名气)

★
jjdg(金币+1): 感谢参与 2011-06-07 15:09:12
引用回帖:
Originally posted by mengxc at 2011-06-07 08:38:30:
第二个printf("n is %d\n", n);已经是在WHILE循环外边了,循环在n=3输出后,又n++,变成4,不满足n++<3,跳出循环

我的理解是,n++是先用n的值再+1。n=3,回到while loop后,应该先和3比较,如果满足,就++,如果不满足就不应该++了,对不对?
3楼2011-06-07 09:46:04
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mengxc

木虫 (著名写手)

【答案】应助回帖

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joansky(金币+5): 2011-06-07 11:17:14
ben_ladeng(金币+2): 欢迎常来参与讨论 2011-06-07 13:10:49
引用回帖:
Originally posted by joansky at 2011-06-07 09:46:04:
我的理解是,n++是先用n的值再+1。n=3,回到while loop后,应该先和3比较,如果满足,就++,如果不满足就不应该++了,对不对?

“n++是先用n的值再+1。n=3,回到while loop后,应该先和3比较"这没错
但是后面的++是不管满足不满足都要执行的。n++就是先取n的值,再加1
4楼2011-06-07 09:55:12
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