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lscser

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jiangwu8888(金币+5): 2011-02-13 11:47:32
jiangwu8888(金币+5): 2011-02-16 21:47:02
当a走80cm后速度减为0,此是e开始滑,说明a运动了2s
即V0=-2a
又0-V0^2=2as=2a*0.8
即-4a^2=2a*0.8
即a=-0.4  (1)
即V0=0.8  (2)
e开始滑时c已经走出1s了,
所以此时Ve=0.8-0.4=0.4
此时e走的路程s=(Ve^2-V0^2)/2a=(0.4^2-0.8^2)/(-2*0.4)=0.6  (3)
2楼2011-02-13 01:08:41
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