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紧急求助-- 一段数据结构论文翻译（赠送10金币）！
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| 在添加新规则15时，通过查找B0的范围搜索树将返回点b70，又发现规则b70 规则索引表的第1项是规则10，新规则15与规则10并非是独立的，所以不能添加进B1；规则索引表的第1项是-1，规则15将与B2中的前一条非-1规则即规则7比较，它们也不是独立的, 所以不能添加进B2；规则索引表的第3项是-1，规则15将与B3中的前一条非-1规则即规则14比较，它们是独立的，所以规则15最终将添加到独立集合B3中。规则15的起点bnew是B0中没有的新端点，需要将bnew添加到B0中，并且为其创建规则索引表(-1，7，15)，同时更新b70的索引表为(10，-1，15)。 |
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ronghg(金币+5, 翻译EPI+1): 谢谢兄弟的工作，是数据结构的一段翻译 2011-01-23 21:59:38
ringzhu(金币+10): 辛苦 2011-02-19 10:48:36
ronghg(金币+5, 翻译EPI+1): 谢谢兄弟的工作，是数据结构的一段翻译 2011-01-23 21:59:38
ringzhu(金币+10): 辛苦 2011-02-19 10:48:36
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when we add a new Rule 15, the search tree will return to the point of B70 through researching the range of B0. Then we find the Role b70 and the item 1 of the index table is Rule 10. The new Rule 15 and Rule 10 are not independent, so we could not add Rule B1; item 1 of the table index is -1. Rule 15 and Rule 7, which is the former rule of B2 and is non-1, are not independent either, so we could not either added B2 here; item 3 of the index table is -1, Rule 15 and Rule 14, which is the former rule of B3 and is -1, are independent, so Rule 15 will eventually be added to the independent set B3. The starting point of Rule 15 is bnew, which is a new endpoint and does not appear in B0. we have to add bnew into Bo, to create a rule index table (-1,7,15), and also to update the index table b70 (10, -1, 15). 实在是有些地方看不明白你想表达什么。根据我自己的理解译成这样 |
2楼2011-01-23 21:39:54