| 查看: 810 | 回复: 2 | |||
| 本帖产生 1 个 翻译EPI ，点击这里进行查看 | |||
hanjing011木虫 (正式写手)
|
[交流]
帮忙校对一小段
|
||
|
2,3,4,5-tetrahydro-7-methoxy-1H-2-benzazepin-1-one is a very important intermediate in our synthesis. But mixtuer of two isomers was obtained when 6-methoxy-3,4-dihydronaphthalen-1(2H)-one oxime was used as the starting material to carry out the Bakemann reaction. This is due to the two groups at the both ends of the C=N double bond are close, which resulted in less selectivity. We guess that trans-6-methoxy-3,4-dihydronaphthalen-1(2H)-one oxime would give 1,3,4,5-tetrahydro-7-methoxy -2H-1-benzazepin-2-one ane cis-6-methoxy-3,4-dihydronaphthalen-1(2H)-one oxime gives 2,3,4,5-tetrahydro-7- methoxy -1H-2-benzazepin-1-one. Therefore, we synthesized and trained the title compound so as to improve the selectivity of Backmann rearrangement. 2,3,4,5-四氢-7-甲氧基-1H-2-苯并氮卓-1-酮是我们合成研究中重要的中间体。但是，用6-甲氧基-3，4-二氢萘-1（2H）酮肟为原料进行贝克曼重排时得到了两种同分异构体的混合物。这是由于C=N双键两端的基团大小相近而导致重排的选择性较差。我们推测，用反式6-甲氧基-3，4-二氢萘-1(2H)酮肟会得到1,3,4,5-四氢-7-甲氧基-2H-1-苯并氮卓-2-酮，顺式酮肟会得到2,3,4,5-四氢-7-甲氧基-1H-2-苯并氮卓-1-酮。因而，我们合成并培养了题目物质以便于提高贝克曼重排的选择性。 |
回复此楼» 猜你喜欢
filecode
已经有7人回复
-
大家散了吧，后缀研究没有意义，别浪费时间了，过好目前的每一天，不要焦虑
已经有4人回复
-
filecode
已经有5人回复
-
求各位大神看下
已经有31人回复
-
咨询面上基金
已经有7人回复
-
影响面上的因素
已经有11人回复
-
8月时间戳变的，举个手。玩一下，释放压力
已经有11人回复
-
一个有机合成实验室都需要哪些设备？
已经有11人回复
-
面上再次挂了，太难了，躺也躺不了，倦也卷不过，小学校之殇！
已经有30人回复
-
好消息？这个有何含义？？？
已经有10人回复
cxsunkun
铁虫 (正式写手)
- 翻译EPI: 1
- 应助: 2 (幼儿园)
- 金币: 1384.8
- 散金: 150
- 帖子: 393
- 在线: 66.8小时
- 虫号: 397945
- 注册: 2007-06-10
- 性别: GG
- 专业: 金属结构材料
2楼2010-07-28 11:32:23
charleygan 
至尊木虫 (著名写手)
chlgan
- 翻译EPI: 99
- 应助: 496 (硕士)
- 贵宾: 0.005
- 金币: 13167.2
- 散金: 15
- 红花: 44
- 帖子: 2396
- 在线: 399.5小时
- 虫号: 859768
- 注册: 2009-09-29
- 性别: GG
- 专业: 应用高分子化学与物理
| 2,3,4,5-tetrahydro-7-methoxy-1H-2-benzazepin-1-one is a very important intermediate in our research. But mixture of two isomers is obtained when 6-methoxy-3,4-dihydronaphthalen-1(2H)-one oxime is used as the starting material to carry out the Bakemann reaction, which resulted from the less selectivity of rearrangement because of the close size of two groups at the both ends of the C=N double bond. We propose that trans-6-methoxy-3,4-dihydronaphthalen-1(2H)-one oxime would give 1,3,4,5-tetrahydro-7-methoxy -2H-1-benzazepin-2-one and cis-6-methoxy-3,4-dihydronaphthalen-1(2H)-one oxime would give 2,3,4,5-tetrahydro-7- methoxy -1H-2-benzazepin-1-one. Therefore, the goal compound is synthesized to improve the selectivity of Backmann rearrangement. |
3楼2010-07-28 11:55:39
100