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[交流] 【求助】开启自旋轨道耦合后的PDOS问题

VO2体系,开启自旋轨道耦合后PDOS异常

如下
    -8.000  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00  0.0000E+00(一列)
      0.000  0.0000E+00  0.0000E+00  0.0000E+00(另一列)

PDOS就是上面两列的无限重复,而上面两列,其中一列三十几行,另一列只有三行,是代表什么意思呢?
INCAR 如下
   SYSTEM =VO2_vasp

Startparameter for this Run:
   NWRITE =     2
   LPETIM =     F        ! write-flag & timer
   LMAXMIX=     4
   ISTART =     1        ! job: 0-new  1-cont  2-samecut
   ICHARG =     11      ! 2 atomic  11 scf
   ISPIN  =     1        ! 1/2
   
Electronic Relaxation 1
   PREC   =     normal
   NELM   =     150
   EDIFF  =     1E-04   stopping-criterion for ELM

Ionic Relaxation
   NSW    =      0    number of steps for IOM
   NBLOCK =      1      inner block;
   KBLOCK =      5      outer block
   IBRION =      2      ionic relax: 0-MD 1-quasi-New 2-CG
   ISIF   =      0      stress and relaxation
   ISYM   =      1
   LCORR  =      T      Harris-correction to forces

   POTIM  =   1.50      time-step for ion-motion
   TEBEG  = 1873.0
   TEEND  = 1873.0      initial temperature
   SMASS  =   3.00      Nose mass-parameter (am)

  Mass of Ions in am

DOS related values:
   ISMEAR =     -5
   SIGMA  =    .20      broadening in eV -4-tet -1-fermi 0-gaus

Electronic Relaxation 2
   IALGO  =     38      algorithm
   LDIAG  =      T      sub-space diagonalisation
   LREAL  =      T      real-space projection
   
   LDAU     = .TRUE.
   LDAUTYPE = 2
   LDAUL    = 2 -1
   LDAUU    = 4.8 0.0
   LDAUJ    = 0.8 0.0
   LWAVE    = .FALSE.

   LSORBIT  = .TRUE.
   

   
   NEDOS   =1000      numberof grid point
   EMIN    =-8         minimum energy for evaluation of DOS   
   EMAX    =14         maximum energy for evaluation of DOS
   LORBIT  =11      
   NPAR    =1

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