| 查看: 269 | 回复: 1 | |||
| 【奖励】 本帖被评价1次,作者forever_9999增加金币 1 个 | |||
| 当前主题已经存档。 | |||
[资源]
【资源】Combinatorial Chemistry: Synthesis, Analysis, Screening
|
|||
|
Gunther Jung. Combinatorial Chemistry: Synthesis, Analysis, Screening. Wiley- VCH, 634 pp. (2000) Combinatorial chemistry is a proven time- and resource-saving synthetic method of outstanding importance for industrial processes. Compound libraries help to save time and money, especially in the search for new drugs, and therefore play a pivotal role in solving the problem of the worldwide increasing demand for new and more active drugs. Not only substances, which are of interest for pharmaceutical chemistry, but also materials, catalysts, and biomolecules such as DNA or oligosaccharides are readily available with high structural diversities. The broad scope of combinatorial sciences is reflected by this book, edited by Gunther Jung: The synthetic methods discussed range from solid-phase to solution-phase synthesis, from preparations of small molecules such as amines or alcohols to those of complex biomolecules. Feasible methods, efficient techniques, new trends in automation, and state-of-the-art fast instrumental analytical and screening methods are presented with many practical tips and tricks for everybody working in combinatorial chemistry. This is the book written by specialists for specialists and for everyone aspiring to become an insider! It is an indispensible source of information for researchers working in organic synthesis, catalysis, biochemistry, and biotechnology, pharmaceutical and clinical chemistry, material sciences, and analytical chemistry. http://rapidshare.com/files/168118579/352729869X.rar http://ifile.it/wmai8u3/352729869x.rar |
» 收录本帖的淘帖专辑推荐
精华帖-好资源 |
» 猜你喜欢
什么脱膜剂可以完全清洗干净啊?
已经有2人回复
暨南大学化学与材料学院赵宇亮院士正在招博士和博后,方向为生物材料和纳米医学
已经有1人回复
有机高分子材料论文润色/翻译怎么收费?
已经有72人回复
可生物降解聚酯正在重塑现代医疗器械
已经有0人回复
26届博士申请
已经有2人回复
PLLA 微球在生物医学领域的研究与应用
已经有1人回复
PLLA 微球的材料特性与制备工艺解析
已经有0人回复
医用聚己内酯(PCL)全解析:从两段式降解到组织工程应用
已经有0人回复
反相硅胶如何再生?
已经有0人回复
2楼2009-11-15 10:46:35













回复此楼