[交流] 【讨论】电池交换电流的求解

Originally posted by 毕卡恩_2009 at 2009-11-12 19:21:
对啊，在强极化区（塔菲尔区），根据斜率和节距可以求出a和b啊，然后a和b之间就差一个传递系数。

Originally posted by honggaoliang at 2009-11-13 10:33:

The transfer coefficient is a measure of the symmetry of the energy barrier, and can range from zero to unity. Chen et al. suggested a symmetric activation energy barrier for the fuel cell applic ...

Originally posted by 毕卡恩_2009 at 2009-11-13 12:38:


我觉得不能吧，a和b是单电极的电化学反应传递系数，用电池的I-E曲线我觉得不合适吧，做单电极的极化曲线，在极化曲线上的tafel区求算就是了。