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友风

铁虫 (小有名气)

[交流] 【求助】用gaussian分析分子内受阻转动的输出

大家好!
我现在想用gaussian 对分子内转动做分析,使用了关键字freq=hindrot 但是对其输出不是很理解,有没有做过这方面的。谢谢!这是输出的一部分:

Hindered Internal Rotation Analysis
Internal coordinate list checked
Check for planar centers
Check reduced barrier height. Cut-off : V/RT =    33.7561
Check for ring deformation
Number of internal rotation degrees of freedom =   3
Check correspondance between vibrational and internal rotation modes
frequencies in cm**-1

                             1         2         3
       Frequencies ---    55.3745  142.9784  241.3514
           44.7008         0.7992   -0.0990   -0.3410
           93.5361         0.4300   -0.9264    0.8480
          116.9105        -0.5194    0.9381   -0.5992
          138.6770         0.2542   -0.3016   -0.3770
          178.5088        -0.3040    0.4544    0.1184
          270.0114        -0.0088    0.2356   -0.8202
----------------------------------------------------------------------------
Identification of rotating group for bond    1 -  5
Iteration  1 RMS(Cart)=  0.10289454 RMS(Int)=  0.03266775
Iteration  2 RMS(Cart)=  0.03384977 RMS(Int)=  0.00086275
Iteration  3 RMS(Cart)=  0.00088711 RMS(Int)=  0.00000040
Iteration  4 RMS(Cart)=  0.00000043 RMS(Int)=  0.00000000
Iteration  1 RMS(Cart)=  0.00000000 RMS(Int)=  0.00000000
Composition of rotating group :
   2   3   4
Geometrical symmetry number =   1
Identification of rotating group for bond    5 -  7
Iteration  1 RMS(Cart)=  0.07021742 RMS(Int)=  0.01967869
Iteration  2 RMS(Cart)=  0.02448239 RMS(Int)=  0.00074294
Iteration  3 RMS(Cart)=  0.00070302 RMS(Int)=  0.00000040
Iteration  4 RMS(Cart)=  0.00000049 RMS(Int)=  0.00000000
Iteration  1 RMS(Cart)=  0.00000000 RMS(Int)=  0.00000000
Composition of rotating group :
   1   2   3   4   6   8
Geometrical symmetry number =   1
Identification of rotating group for bond    7 -  9
Iteration  1 RMS(Cart)=  0.06018718 RMS(Int)=  0.01295981
Iteration  2 RMS(Cart)=  0.02282442 RMS(Int)=  0.00080227
Iteration  3 RMS(Cart)=  0.00074522 RMS(Int)=  0.00000047
Iteration  4 RMS(Cart)=  0.00000080 RMS(Int)=  0.00000000
Iteration  1 RMS(Cart)=  0.00000000 RMS(Int)=  0.00000000
Composition of rotating group :
  10
Geometrical symmetry number =   1
Check constant moment of inertia assumption for bond   1 -  5
  Free rotor partition function : Estimated error   =   18.622 %
  External rot. free rotor partition function. Estimated error   =  -34.359 %
  Check steric hindrance using Lennard-Jones Potential
  Check potential periodicity
  Well about Phi = 120.00 degrees is not accessible : (V-V0)/RT = ********
  Well about Phi = 240.00 degrees is not accessible : (V-V0)/RT = ********
Number of accessible wells :   1
Check constant moment of inertia assumption for bond   5 -  7
  Free rotor partition function : Estimated error   =   83.334 %
  External rot. free rotor partition function. Estimated error   =   67.865 %
  Check steric hindrance using Lennard-Jones Potential
  Check potential periodicity
Number of accessible wells :   3
Check constant moment of inertia assumption for bond   7 -  9
  Free rotor partition function : Estimated error   =   60.639 %
  External rot. free rotor partition function. Estimated error   =   70.650 %
  Check steric hindrance using Lennard-Jones Potential
  Check potential periodicity
  No minimum about Phi = 120.00 degrees
Number of accessible wells :   3
我的问题是他得到的内转有三个频率,而在与那个谐振对应的时候有6个,不是一个谐振模减少一个,内转才增加一个吗?
谢谢大侠!
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