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风雨182木虫 (正式写手)
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【求助】请教高手
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由公式3-1和3-2计算出样品的晶相组成和晶粒大小列于表5-1中。由图中可以看出，纯TiO2中锐钛矿相占51%，N掺杂TiO2中锐钛矿相占16%，S掺杂TiO2中锐钛矿相占77%。与纯TiO2的晶相组成相比，N掺杂促进了锐钛矿型向金红石型的转化，而S的掺杂抑制了高温下锐钛矿型向金红石型的转化。N-S共掺杂的TiO2中锐钛矿相占72%，说明以S掺杂抑制金红石相生长起主要作用。从粒径大小来看，N-S共掺杂TiO2的平均粒径是11.64 nm，量子尺寸效应最明显。 请不要直接复制翻译软件！！！！ |
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Calculation results of both the phase composition
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风雨182(金币+20,VIP+0): 9-24 10:35
风雨182(金币+20,VIP+0): 9-24 10:35
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and grain sizes of TiO2 samples based on equations of 3-1 and 3-2 are given in Tab. 5-1. from the fig, it can be seen that there are 51% 锐钛矿 phase in a pure TiO2 sample, 16% in a N-doped sample and 77% in a S-doped sample. Compared with the phase composition of a pure TiO2 sample, it can be said that N-doping can promote the conversion of 锐钛矿phase to 金红石型 phase and S-doping inhibits this conversion at high temperatures. The evidence of 72% 锐钛矿 phase in a N-S co-doped TiO2 sample suggests that S-doping plays a key role in inhibiting the growing of 金红石型 phase. regarding grain sizes, the most notable quantum dimensional effect is found in a N-S doped sample with an averaging grain size 11.64 nm. note: there is no place in your test where a figure # is given. only a table # of 5-1 |
2楼2009-09-24 03:11:32
