| 查看: 185 | 回复: 1 | |||
| 当前主题已经存档。 | |||
| 【有奖交流】积极回复本帖子，参与交流，就有机会分得作者 白欣 的 20 个金币 | |||
[交流]
【求助】请高手帮忙解题！
|
|||
|
Cryptarithmetic Cryptarithmetic involves arithmetic on numbers where the digits have been encoded as letters. A cryptarithmetic puzzle usually requires you to work out which digit each letter stands for. For example, if you are told that someone has to use some eye medication twice in order to see, so: USE + USE = SEE you have to work out that E stands for 0, S stands for 5, and U stands for 2, so the unencoded expression is: 250 + 250 = 500 In this assignment the task is simplified to repeatedly working out the result of a cryptarithmetic operation given the encoding scheme, e.g. given what the letters stand for and the following expression: USE + USE your program will have to unencode the encoded numbers into ints, do the arithmetic operation and encode the result, so as to work out that: USE + USE = SEE (Hint: Make sure that you understand the String methods, such as indexOf, before you try to work out how to unencode and encode.) The arithmetic is to be done as integer arithmetic, e.g. 3/2 = 1, and all numbers will be such that the actual arithmetic can be done with ints, and will never involve negative numbers. (You can look up more about cryptarithmetic on e.g. Wikipedia, but you may not use any code that you find there, or elsewhere, which relates to cryptarithmetic — not even as a starting point for your own code.) User Interaction The program must first explain to the user how to use it. It must then repeatedly ask the user what they want to do next. Whenever the user enters "Cryptarithmetic" (without quotes) after being asked what to do next, the program will: Prompt the user to enter a one operation cryptarithmetic expression, starting with the encoding. Read 4 Strings, using Scanner's next() method. The strings represent: The encoding scheme, identifying the letters for digits in order from the letter for 0, e.g. "EAUBCSDFGH" (without quotes) would show that 0 is represented by E, 1 is represented by A, 2 is represented by U, ..., 5 is represented by S, ... 9 is represented by H. The first operand, e.g. "USE" (without quotes). The operator, e.g. "+" (without quotes). The second operand, e.g. "USE" (without quotes). If it was a valid cryptarithmetic encoding and expression, output (with appropriate spacing) the cryptarithmetic expression with = and result for what the user entered, e.g.: USE + USE = SEE Otherwise output an error message. The encoding and expression are to be considered valid, if (and only if) all the following are true: The encoding string contains exactly 10 characters. Every character in the encoding string is an upper case letter. Every character in the encoding string is different from every other character in the encoding string. Every character in the first operand is in the encoding string. The operator string contains exactly one character. The character in the operator string is one of the standard Java arithmetic operators: +, -, *, /, %. Every character in the second operand is in the encoding string. If the user enters anything other than "Cryptarithmetic" (without quotes) after being asked what to do next, the program must stop, returning from the main(). This link shows an example of user interaction of the appropriate form. (The user has indented each thing they enter so that you can see which lines they enter and which the computer has produced. This has only been done for ease of reading. Your program will be tested without such indenting.) You must make up your own (appropriate) messages to the user, but your program must accept input of exactly the form specified, and display the cryptarithmetic results as specified. (We must be able to test your program automatically by feeding it input of the specified form and easily comparing the output produced with the expected output 主要就是说E A U B C S D F G H 0 1 2 3 4 5 6 7 8 9 这些对应，然后进行一个循环运算的编程，有高手有答案的，请帮忙，万分感谢！！！ [ Last edited by 白欣 on 2009-9-10 at 23:01 ] |
回复此楼» 猜你喜欢
299求调剂
已经有8人回复
-
一志愿北京理工大学本科211材料工程294求调剂
已经有6人回复
-
300求调剂，材料科学英一数二
已经有8人回复
-
招收生物学/细胞生物学调剂
已经有5人回复
-
070305高分子化学与物理 304分求调剂
已经有7人回复
-
289求调剂
已经有13人回复
-
一志愿哈尔滨工业大学材料与化工方向336分
已经有9人回复
-
081200-11408-276学硕求调剂
已经有6人回复
-
调剂求院校招收
已经有5人回复
-
调剂310
已经有8人回复
jjdg
版主 (知名作家)
- 程序强帖: 9
- 应助: 223 (大学生)
- 贵宾: 3.926
- 金币: 51005.2
- 红花: 238
- 帖子: 7227
- 在线: 474.2小时
- 虫号: 27000
- 注册: 2003-10-21
- 专业: 药物代谢与药物动力学
- 管辖: 程序语言
2楼2009-10-09 11:58:56
