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Pt负载量问题求助
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各位大神，文献中材料合成过程为：400 mg of the as-prepared MOF-253was dispersed with a certain amount of H2PtCl6·6H2O (0.0211, 0.0444, and 0.1 mg) in acetonitrile (15 mL). The obtained solution was then heated at 85 °C in a Teflon-capped autoclave for 72 h. The formed solids were collected by centrifugation and then immersed in acetonitrile (15 mL) for 3 days. The solvent was replaced with fresh acetonitrile every 24 h. The products were then collected by filtration and dried at 150 °C for 12 h in vacuum. The obtained Pt@MOF-253 solids were then heat-treated at 900 °C at a ramp rate of 1 °C min–1 for 4 h in Ar atmosphere. Finally, the samples were pickled with NaOH solution at 70 °C for 6 h to remove inactive Al-metal species and residues, followed by thorough washing in deionized water until the resultant solution had a neutral pH, before finally being dried under vacuum at 80–110 °C. For simplicity, the as-obtained catalysts were labelled as Pt@N/C-x, where x represents 2%, 5%, and 10% of Pt-loading in the catalyst. 400 mg MOF-253分别与H2PtCl6·6H2O (0.0211, 0.0444, and 0.1mg)混合，制备出Pt@N/C，最终合成催化剂中Pt含量分别对应为2%, 5%, and 10%。以2%Pt负载量为例，我算了下，400 mg MOF-253去掉Al、O、H等元素（只保留C/N）为240.8mg，0.0211H2PtCl6·6H2O中Pt的含量为0.00794mg，严重低于2%。特此向您求教Pt负载量是怎么确定的。谢谢~ 文章来源《Robust MOF-253-derived N-doped carbon confinement of Pt single nanocrystal electrocatalysts for oxygen evolution reaction》 |
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