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xhdeng252

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[交流] 【求助】三维透射图

各位大侠，我这里有个用Matlab编写的透射率随角频率和入射角变化的程序（见附件），但不知如何输出透射率随角频率和入射角变化的三维图，不知怎样写出这种三维图形的输出代码？希望能得到您的指点，万分感谢！

附：
%计算 transmittance
clear;
clc;

c=3e8;
d1=6e-3;
d2=12e-3;
d3=36e-3;
d4=40e-3;
d5=10e-3;
% angle=60*pi/180;
%%
for  j=1:1000
w(1)=1.0e9;
% w(j+1)=w(j)+0.0014*1e9*2*pi;
w(j+1)=w(j)+0.02*1e9;
k0(j)=w(j)/c;
      e1(j)=1.21-100/(w(j)/1e9)^2;
      u1(j)=1-100/(w(j)/1e9)^2;
      e2(j)=4;
      u2(j)=1;
      for k=1:1000
         theta(1)=0;
         theta(k+1)= theta(k)+0.16;
         angle(k)= theta(k)*pi/180;
            % Ma       NIM
pz1(j,k)=k0(j)*sqrt(e1(j))*sqrt(u1(j))*sqrt(1-sin(angle(k))^2/(e1(j)*u1(j)));
q1(j,k)=sqrt(e1(j))/sqrt(u1(j))*sqrt(1-sin(angle(k))^2/(e1(j)*u1(j)));
Ma = zeros(2,2);
Ma(1,1) = cos(pz1(j,k)*d1);
Ma(1,2) = i*sin(pz1(j,k)*d1)/q1(j,k);
Ma(2,1) = i*q1(j,k)*sin(pz1(j,k)*d1);
Ma(2,2) = cos(pz1(j,k)*d1);
            %Mb          PIM
pz2(j,k)=k0(j)*sqrt(e2(j))*sqrt(u2(j))*sqrt(1-sin(angle(k))^2/(e2(j)*u2(j)));
q2(j,k)=sqrt(e2(j))/sqrt(u2(j))*sqrt(1-sin(angle(k))^2/(e2(j)*u2(j)));
Mb = zeros(2,2);
Mb(1,1) = cos(pz2(j,k)*d2);
Mb(1,2) = i*sin(pz2(j,k)*d2)/q2(j,k);
Mb(2,1) = i*q2(j,k)*sin(pz2(j,k)*d2);
Mb(2,2) = cos(pz2(j,k)*d2);

            % Mc       NIM
  % pz1(j)=k0(j)*sqrt(e1(j))*sqrt(u1(j))*sqrt(1-sin(angle)^2/(e1(j)*u1(j)));
  % q1(j)=sqrt(e1(j))/sqrt(u1(j))*sqrt(1-sin(angle)^2/(e1(j)*u1(j)));
Mc = zeros(2,2);
Mc(1,1) = cos(pz1(j,k)*d3);
Mc(1,2) =i*sin(pz1(j,k)*d3)/q1(j,k);
Mc(2,1) = i*q1(j,k)*sin(pz1(j,k)*d3);
Mc(2,2) = cos(pz1(j,k)*d3);
;             %Md       PIM
%    pz2(j)=k0(j)*sqrt(e2(j))*sqrt(u2(j))*sqrt(1-sin(angle)^2/(e2(j)*u2(j)));
%    q2(j,k)=sqrt(ey(j)*ux(j)-ux(j)/uz(j)*sin(angle(k))^2)/ux(j);
%    Md = zeros(2,2);
%    Md(1,1) = cos(pz1(j)*d4);
%    Md(1,2) = i*sin(pz1(j)*d4)/q1(j);
%    Md(2,1) = i*q1(j)*sin(pz1(j)*d4);
%    Md(2,2) = cos(pz1(j)*d4);
Md = zeros(2,2);
Md(1,1) = cos(pz2(j,k)*d4);
Md(1,2) = i*sin(pz2(j,k)*d4)/q2(j,k);
Md(2,1) = i*q2(j,k)*sin(pz2(j,k)*d4);
Md(2,2) = cos(pz2(j,k)*d4);
;       %Me          PIM
%    pz3(j)=k0(j)*sqrt(e3(j))*sqrt(u3(j))*sqrt(1-sin(angle)^2/(e3(j)*u3(j)));
%    q3(j)=sqrt(e3(j))/sqrt(u3(j))*sqrt(1-sin(angle)^2/(e3(j)*u3(j)));
%    Me = zeros(2,2);
%    Me(1,1) = cos(pz1(j)*d5);
%    Me(1,2) = i*sin(pz1(j)*d5)/q1(j);
%    Me(2,1) = i*q1(j)*sin(pz1(j)*d5);
%    Me(2,2) = cos(pz1(j)*d5);
Me = zeros(2,2);
Me(1,1) = cos(pz2(j,k)*d5);
Me(1,2) = i*sin(pz2(j,k)*d5)/q2(j,k);
Me(2,1) = i*q2(j,k)*sin(pz2(j,k)*d5);
Me(2,2) = cos(pz2(j,k)*d5);

%    X=((Ma*Mb)^6*(Mc*Md)^6)^2;
%    X=((Ma*Mb)^8*(Mc*Md)^8)^3;
%    X=((Ma*Mb)^8*(Mc*Md)^8*(Ma*Mb)^8*(Mc*Md)^8*(Ma*Mb)^8*(Mc*Md)^8)^1;
%    X=(Ma*Mb)^8*(Ma*Mb*Ma*Mc)^5*Ma*Mb*Ma*(Mb*Ma)^8;
%    X=(Ma*Mb)^16;%s0;
%    X=(Ma*Mb)^4*(Mc)*(Mb*Ma)^4;%s1
%    X=(Ma*Mb)^5*(Mc)*(Mb*Ma)^5*(Md)*(Ma*Mb)^5*(Mc)*(Mb*Ma)^5;%s2
X=(Ma*Mb)^8*(Mc)*(Mb*Ma)^8*(Md)*(Ma*Mb)^8*(Mc)*(Mb*Ma)^8*(Me)*(Ma*Mb)^8*(Mc)*(Mb*Ma)^8*(Md)*(Ma*Mb)^8*(Mc)*(Mb*Ma)^8;  %s3
%    X=(Ma*Mb)^6*(Mc)*(Mb*Ma)^6*(Md)*(Ma*Mb)^6*(Mc)*(Mb*Ma)^6*(Me)*(Ma*Mb)^6*(Mc)*(Mb*Ma)^6*(Md)*(Ma*Mb)^6*(Mc)*(Mb*Ma)^6;
%    X=(Ma*Mb)^6*(Mc)*(Mb*Ma)^6*(Md)*(Ma*Mb)^6*(Mc)*(Mb*Ma)^6;
%    X=(Ma*Mb)^2*(Mc)*(Mb*Ma)^2*(Md)*(Ma*Mb)^2*(Mc)*(Mb*Ma)^2*(Me)*(Ma*Mb)^2*(Mc)*(Mb*Ma)^2*(Md)*(Ma*Mb)^2*(Mc)*(Mb*Ma)^2;
t(j,k) =2/((X(1,1)+X(2,2))-(cos(angle(k))*X(1,2)+X(2,1)/cos(angle(k))));

T(j,k)=abs(t(j,k)^2);
R(j,k)=1-T(j,k);
w0(j)=w(j)/1e9;
      end
end
%
% x=w0(1:1000);
% y=angle(1:1000);
% z=T(1:1000);
% [x,y]=meshgrid(x,y);
% plot3(x,y,z)
% shading interp

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