10楼: Originally posted by 独孤神宇 at 2018-10-24 10:50:44
clear;
a=-0.6;
b=-0.9;
x=-3:0.01:3;
f=4*x.^2.*(x.^2-1)*a^2+8*x.^2.*((sin(x*pi/2)).^2-x.^2)*a*b+4*((sin(x*pi/2)).^2-x.^2).^2*b^2+(sin(x*pi)).^2;
z=[];
for i=1:length(x)
       if abs(f(i))& ...

11楼: Originally posted by nuomandi521 at 2018-10-24 17:08:56
其实我是想把f(x)=0时，x的值赋给z。
所以这个for循环的目标不太对。
仍然无比感谢！...

12楼: Originally posted by 独孤神宇 at 2018-10-24 18:47:01
真是无语，你直接将问题描述清楚不就行了。。

clear;
a=-0.6;
b=-0.9;
x=-3:0.01:3;
f=4*x.^2.*(x.^2-1)*a^2+8*x.^2.*((sin(x*pi/2)).^2-x.^2)*a*b+4*((sin(x*pi/2)).^2-x.^2).^2*b^2+(sin(x*pi)).^2;
z=[ ...