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北京石油化工学院2026年研究生招生接收调剂公告
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hitcs

铜虫 (初入文坛)

[求助] 求助,用1stopt 5.0解非线性方程组,两次得到的解不唯一?什么原因,大神帮忙 已有1人参与

代码如下,9元非线性方程组,得到的结果不唯一:
Parameter x1=0.095843301[0,0.095843301],x2=0.034539474[0,0.034539474],x3=0.004934211[0,0.004934211],x4=0.044258373[0,0.044258373],x5=0.008672249[0,0.008672249],x6=0.046202153[0,0.046202153],x7=0.015550239[0,0.015550239],x8=0.5[0,0.5],x9=0.25[0,0.25];
Function
0=0.044258373*x1+0.044258373*((5.305*10^3/1.518)^0.5)*x1/x2^2*(1.518*x2^4*x8^2*x9/(2+2*((5.305*10^3/1.518)^0.5)*x1/x2^2)^4)^(1/6)-0.095843301*x4-2*0.095843301*(1.109*10^54*x4^4*x9^3)^(1/2);
0=0.044258373*x2+2*0.044258373*(1.518*x2^4*x8^2*x9/(2+2*((5.305*10^3/1.518)^0.5)*x1/x2^2)^4)^(1/6)-0.034539474*x4-2*0.034539474*(1.109*10^54*x4^4*x9^3)^(1/2);
0=0.044258373*x3+0.044258373*(2.012*x3)^(1/2)-0.004934211*x4-2*0.004934211*(1.109*10^54*x4^4*x9^3)^(1/2);
0=0.044258373*x5+2*0.044258373*(3.131*10^32*x5^4*x9^3)^(1/2)-0.008672249*x4-2*0.008672249*(1.109*10^54*x4^4*x9^3)^(1/2);
0=0.044258373*x6+0.044258373*(1.077*10^12*x6^2*x9)^(1/2)-0.046202153*x4-2*0.046202153*(1.109*10^54*x4^4*x9^3)^(1/2);
0=0.044258373*x7+0.044258373*(2.108*10^16*x7^2*x9^3)^(1/2)-0.015550239*x4-2*0.015550239*(1.109*10^54*x4^4*x9^3)^(1/2);
0=0.044258373*x8+0.5*0.044258373*((1.518*x2^4*x8^2*x9)^(1/6))*((2+2*(5.305*10^3/1.518)^0.5*x1/x2^2)^(1/3))-0.5*x4-2*0.5*(1.109*10^54*x4^4*x9^3)^(1/2);
0=0.044258373*x9+1.5*0.044258373*(1.109*10^54*x4^4*x9^3)^(1/2)+1.5*0.044258373*(3.131*10^32*x5^4*x9^3)^(1/2)+0.5*0.044258373*(1.077*10^12*x6^2*x9)^(1/2)+1.5*0.044258373*(2.108*10^16*x7^2*x9^3)^(1/2)+0.5*0.044258373*((5.305*10^3/1.518)^0.5)*x1/x2^2*(1.518*x2^4*x8^2*x9/(2+2*((5.305*10^3/1.518)^0.5)*x1/x2^2)^4)^(1/6)+0.5*0.044258373*(1.518*x2^4*x8^2*x9/(2+2*(5.305*10^3/1.518)^0.5*x1/x2^2)^4)^(1/6)-0.25*x4-2*0.25*(1.109*10^54*x4^4*x9^3)^(1/2);
0=x1+x2+x3+x4+x5+x6+x7+x8+x9+(1.109*10^54*x4^4*x9^3)^(1/2)+(3.131*10^32*x5^4*x9^3)^(1/2)+(1.077*10^12*x6^2*x9)^(1/2)+(2.108*10^16*x7^2*x9^3)^(1/2)+(5.305*10^3/1.518)^0.5*x1/x2^2*(1.518*x2^4*x8^2*x9/(2+2*(5.305*10^3/1.518)^0.5*x1/x2^2)^4)^(1/6)+(1.518*x2^4*x8^2*x9)^(1/6)*(2+2*(5.305*10^3/1.518)^0.5*x1/x2^2)^(1/3)+(1.518*x2^4*x8^2*x9/(2+2*(5.305*10^3/1.518)^0.5*x1/x2^2)^4)^(1/6)+2*(2.012*x3)^(1/2)-1;
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dingd

铁杆木虫 (职业作家)

【答案】应助回帖


独孤神宇: 金币+1 2018-06-08 19:36:54
一楼的问题还是可以大概率得到唯一解的:

x1: 0.000415258421410393
x2: 0.0295645164484108
x3: 1.36712379593572E-5
x4: 2.29288172384266E-14
x5: 2.47606393479552E-9
x6: 1.35850617795293E-7
x7: 2.67957126216714E-9
x8: 0.427499066472031
x9: 0.121967698482867
3楼2018-06-08 17:19:16
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quanluhan

新虫 (初入文坛)

楼主 解决问题没?我也遇到了相同的问题,我也是解9元非线性方程组,感觉结果明显不对,但是代码也不知道哪里错了。。。请大神赐教啊
2楼2018-06-08 14:59:25
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状元糕

铁虫 (小有名气)

大神,能不能分享一份1stopt5.o给我,非常谢谢!2207929801@qq.com
潜力无限
4楼2018-07-04 22:54:51
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