24小时热门版块排行榜    

查看: 105  |  回复: 0
当前主题已经存档。

yolanda8608

[交流] 请教一个有相互作用的统计题目

For interacting systems, it may not be possible to solve the statistical mechanics exactly or even in any well-controlled approximation scheme. Sometimes, however, it is possible to make useful progress just using dimensional analysis.

(a) Consider a gas of classical particles of mass m in a volume V interacting via a pair potential U(r). Sketch a typical form of U(r). Suppose that for a particular class of substances, U(r) has the form U(r) = ε u(r/σ). The meaning of this is that the energy scale is set by ε and the length scale by σ. For example, different gases might have different hard core radii σ and binding energies ε. Working in the canonical ensemble, show that all substances in this class have the same equation of state when expressed in suitably scaled variables. i.e. p* = Π(v*, T*), where starred quantities are scaled pressure, volume per particle and temperature, and Π is a function that dimensional considerations alone cannot determine.

(b) Show that if there is a critical point for this class of fluids, then pcvc/Tc is a constant independent of the particular fluid.

(c) The above theory works very well for gases like Neon, but significant departures are observed at low temperatures for gases like He and H2. These are due to quantum effects.
By dimensional analysis, show that the scaled equation of state should have the form p* = Π(v*, T*, η) where Π is some function that we cannot determine by these dimensional considerations alone, and η = h /[σ mε ].

(d) Classically, the critical temperature kBTc/ε is a constant, but quantum mechanically, it depends on η. By plotting an appropriate graph (you may use a computer if you wish) estimate the critical temperature of the isotope 3He. You will need the following data.
                   4He              H2
kBTc/ε             0.529          0.896
σ (Å             2.56            2.93
ε/kB (K)         10.2              37
You should justify what assumptions you find it necessary to make. The mass of the proton is 1.67 × 10−27 kg, and kB = 1.38 × 10−23 J K−1.

(e) In part (c), why did we use σ for the length scale and not v1/3 (v ≡ V/N)?
回复此楼

» 猜你喜欢

已阅   回复此楼   关注TA 给TA发消息 送TA红花 TA的回帖
相关版块跳转 我要订阅楼主 yolanda8608 的主题更新
普通表情 高级回复 (可上传附件)
信息提示
请填处理意见