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[求助]
1stopt复数拟合 已有1人参与
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Title "Zcalculation"; complexstr j; Parameters R1,L1,R2,L2,R3,L3; Variable x,Z; Function Z=R1+(2000*pi*x)*L1*1j+(((((((R3^(-1))+(((2000*pi*x)*L3*1j)^(-1)))^(-1))+(2000*pi*x)*L2*1j)^(-1))+(R2^(-1)))^(-1)); Data; //x,Z 0.02 0.09208+0.021296228j 1 0.14407+0.825987526j 2 0.2094+1.635136116j 3 0.31065+2.428765239j 4 0.44347+3.201157196j 5 0.60245+3.947096943j 10 1.596+7.27215855j 15 2.585+10.04304322j 20 3.398+12.51484828j 25 4.045+14.85659141j 30 4.574+17.14744073j 35 5.024+19.41818386j 40 5.424+21.67950221j 45 5.792+23.93705066j 50 6.139+26.18831591j 55 6.47+28.43047055j 60 6.791+30.66445705j 65 7.102+32.89310284j 70 7.406+35.10666899j 75 7.703+37.31269531j 80 7.995+39.50866854j 85 8.28+41.69490283j 90 8.559+43.87611057j 95 8.832+46.0450661j 100 9.1+48.20459685j 各位高手，我想拟合出一个等效阻抗网络的参数，但程序跑完不对，是版本太低无法进行复数计算吗还是程序本身有问题？高版本的大神能否代跑一下，十分感谢！！！ 发自小木虫Android客户端 |
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供参考： 均方差(RMSE): 0.0183857990609202 残差平方和(SSE): 0.0169018803554267 相关系数(R): 0.999991432720333 相关系数之平方(R^2): 0.999982865514064 修正R平方(Adj. R^2): 0.999980417800885 确定系数(DC): 0.999982138261661 F统计(F-Statistic): 110537.325025246 参数 最佳估算 -------------------- ------------- r1 0.136750324611777 l1 6.69930510937323E-5 r2 15.9609745096602 l2 2.69979007419202E-5 r3 5.08185436043915 l3 3.55774168751977E-5 |
2楼2018-01-08 22:45:44
3楼2018-01-09 15:00:59
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求大神帮忙代跑一个程序，其中y1和y6,y7的数据值不够准确，不知道能不能缺参数求解 ODEAlgorithm = RKF45; Parameters k(6)[0,10000]; Variable x,y(7); ODEStep = 1; ODEFunction y1'=-0.01*k1*y1; y2'=0.01014*k1*y1-0.01*k2*y2; y3'=0.006389*k2*y2+0.00697*k5*y6-0.01*k3*y3; y4'=0.010217*k3*y3-0.01*k4*y4; y5'=0.004681*k4*y4+0.004783*k2*y2+0.003333*k5*y6+0.003099*k6*y7; y6'=-0.01*k5*y6; y7'=-0.01*k6*y7; Data; 0,0.415,0,0,0,0,0.301,0.284 0.4174,0.0010,0.0000,0.3415,0.0021,0.6131,0.0000,0.0000 0.4826,0.0000,0.0000,0.3733,0.0023,0.5855,0.0000,0.0000 0.5720,0.0280,0.0000,0.3329,0.0012,0.6356,0.0000,0.0000 0.6176,0.0000,0.0000,0.3268,0.0016,0.6527,0.0000,0.0000 0.7765,0.0000,0.0000,0.2512,0.0012,0.7368,0.0000,0.0000 1.0455,0.0010,0.0000,0.0672,0.0019,0.9201,0.0000,0.0000 |
4楼2018-01-11 21:13:16
