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汕头大学海洋科学接受调剂
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[求助] 大神帮忙看下matlab代码如何设置输出程序,非常感谢!

我的程序是fsolve的39个非线性方程,跪求大神帮忙看下,如何设置输出代码,使所有输出的结果全部都位于0~1之间,跪谢!

function f=myfun1000(N)
global number;         
number=number+1;
b1=0.6625;a1=0.378333333;b2=0.25;a2=0.149019608;b3=0.208333333;a3=0.006578947;p=1E-12;%a1=SiO2;a2=Al2O3;a3=Cr2O3;b1=CaO;b2=MgO;b3=FeO;
k1=281.3950532;
k2=8065.856887;
k3=6410.811308;
k4=30.06055264;
k5=71.99830518;
k6=139.8574962;
k7=268.7249903;
k8=1.30309E+13;
k9=3.58229854;
k10=67.33736511;
k11=0.000903471;
k12=0.000999156;
k13=0.000197228;
k14=7.569522933;
k15=38.3802878;
k16=12.59153449;
k17=6.684150735;
k18=4.193535028;
k19=4.065756496;
k20=11.26860548;
k21=4.664740682;
k22=348.1168847;
k23=1189.415788;
k24=1956.28233;
k25=232.7280509;
k26=28.91832018;
k27=3691.794536;
k28=1243.435699;
k29=1.042678642;
k30=1917.860835;
k31=517.7897451;
k32=239542.0967;
k33=31930502.63;
f(1)=N(1)+N(2)+N(3)+N(4)+N(5)+N(6)+N(7)+N(8)+N(9)+N(10)+N(11)+N(12)+N(13)+N(14)+N(15)+N(16)+N(17)+N(18)+N(19)+N(20)+N(21)+N(22)+N(23)+N(24)++N(25)+N(26)+N(27)+N(28)+N(29)+N(30)+N(31)+N(32)+N(33)+N(34)+N(35)+N(36)+N(37)+N(38)+N(39)-1;
f(2)=a3*(N(2)+N(7)+N(8)+N(9)+N(20)+N(21)+N(24)+2*N(27)+N(33)+2*N(34)+N(35)+N(36)+2*N(37)+2*N(38)+2*N(39))-a1*(N(6)+0.5*N(15)+N(16)+0.5*N(17)+1.5*N(18)+0.5*N(19)+N(23)+N(26));
f(3)=a3*(N(4)+N(10)+2*N(11)+N(12)+6*N(13)+7*N(14)+N(22)+N(25)+3*N(27)+N(34)+N(35))-a2*(N(6)+0.5*N(15)+N(16)+0.5*N(17)+1.5*N(18)+0.5*N(19)+N(23)+N(26));
f(4)=a3*(0.5*N(1)+N(7)+2*N(8)+3*N(9)+N(10)+N(11)+3*N(12)+6*N(13)+12*N(14)+N(15)+N(16)+N(28)+2*N(29)+N(30)+N(33)+N(34)+2*N(35)+N(36)+N(37)+2*N(38)+3*N(39))-b1*(N(6)+0.5*N(15)+N(16)+0.5*N(17)+1.5*N(18)+0.5*N(19)+N(23)+N(26));
f(5)=a3*(0.5*N(3)+N(20)+2*N(21)+N(22)+N(23)+N(36)+N(37)+N(38)+N(39))-b2*(N(6)+0.5*N(15)+N(16)+0.5*N(17)+1.5*N(18)+0.5*N(19)+N(23)+N(26));
f(6)=a3*(0.5*N(5)+2*N(24)+N(25)+N(26)+2*N(28)+2*N(29)+3*N(30)+3*N(31)+2*N(32)+N(33))-b3*(N(6)+0.5*N(15)+N(16)+0.5*N(17)+1.5*N(18)+0.5*N(19)+N(23)+N(26));
f(7)=N(7)-k1*N(1)*N(2);
f(8)=N(8)-k2*N(1)^2*N(2);
f(9)=N(9)-k3*N(1)^3*N(2);
f(10)=N(10)-k4*N(1)*N(4);
f(11)=N(11)-k5*N(1)*N(4)^2;
f(12)=N(12)-k6*N(1)^3*N(4);
f(13)=N(13)-k7*N(1)*N(4)^6;
f(14)=N(14)-k8*N(1)^12*N(4)^7;
f(15)=N(15)-k9*N(1)*N(6)^0.5*p^0.75;
f(16)=N(16)-k10*N(1)*N(6);
f(17)=N(17)-k11*N(6)^0.5/p^0.75;
f(18)=N(18)-k12*N(6)^1.5/p^0.75;
f(19)=N(19)-k13*N(6)^0.5*p^0.75;
f(20)=N(20)-k14*N(2)*N(3);
f(21)=N(21)-k15*N(2)*N(3)^2;
f(22)=N(22)-k16*N(3)*N(4);
f(23)=N(23)-k17*N(3)*N(6);
f(24)=N(24)-k18*N(2)*N(5)^2;
f(25)=N(25)-k19*N(4)*N(5);
f(26)=N(26)-k20*N(5)*N(6);
f(27)=N(27)-k21*N(2)^2*N(4)^3;
f(28)=N(28)-k22*N(1)*N(5)^2*p^0.75;
f(29)=N(29)-k23*N(1)^2*N(5)^2*p^0.5;
f(30)=N(30)-k24*N(1)*N(5)^3*p^0.5;
f(31)=N(31)-k25*N(5)^3*p^0.5;
f(32)=N(32)-k26*N(5)^2*p^0.5;
f(33)=N(33)-k27*N(1)*N(2)*N(5);
f(34)=N(34)-k28*N(1)*N(2)^2*N(4);
f(35)=N(35)-k29*N(1)^2*N(2)*N(4);
f(36)=N(36)-k30*N(1)*N(2)*N(3);
f(37)=N(37)-k31*N(1)*N(2)^2*N(3);
f(38)=N(38)-k32*N(1)^2*N(2)^2*N(3);
f(39)=N(39)-k33*N(1)^3*N(2)^2*N(3);
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