2楼: Originally posted by alober at 2016-11-29 16:42:10
楼主是不是打错了？如果指数里是正的x^2则积分不收敛。猜测可能是-x^2
\int_{0}^{\infty}e^{-x^2+xt}dx=e^{\frac{t^2}{4}}\int_{0}^{\infty}e^{-(x-t/2)^2}dx=e^{\frac{t^2}{4}}\int_{\frac{t}{2}}^{\infty}e^{-x^ ...