[x,y]=solve('x^2+2*y^2=17','x^2-x*y+y^2=7','x,y')

x =
[           -3]
[            3]
[  1/3*3^(1/2)]
[ -1/3*3^(1/2)]

y =
[           -2]
[            2]
[  5/3*3^(1/2)]
[ -5/3*3^(1/2)]

2楼: Originally posted by FMStation at 2016-09-09 22:53:34
http://zhidao.baidu.com/question/7970831.html


=solve('x^2+2*y^2=17','x^2-x*y+y^2=7','x,y')

x =





y =




...

syms x y
S = solve([sin(x)^2 == cos(y), 2*x == y],...
        [x, y], 'ReturnConditions', true);
S.x
S.y
S.conditions
S.parameters

ans =
pi*k - asin(3^(1/2)/3)
asin(3^(1/2)/3) + pi*k
ans =
2*pi*k - 2*asin(3^(1/2)/3)
2*asin(3^(1/2)/3) + 2*pi*k
ans =
in(k, 'integer')
in(k, 'integer')
ans =
k

4楼: Originally posted by FMStation at 2016-09-11 16:08:21
https://www.mathworks.com/help/symbolic/solve.html

syms x y
S = solve(,...
        , 'ReturnConditions', true);
S.x
S.y
S.conditions
S.parameters


ans =
pi*k - asin(3^(1/2)/3)
asin(3^(1/2)/ ...