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jacket114111: ½ð±Ò+2, ¡ïÓаïÖú, лл£¬ÓÉÓÚ×Ô¼º¶ÔµÍͨÂ˲¨Æ÷ûÓÐÌ«¶àÑо¿£¬ËùÒÔÏ£ÍûÄܹ»µÃµ½Ò»¸ö¿ÉÒÔÖ±½ÓʹÓõijÌÐò£¬ËùÒÔÕâ¸ö³ÌÐòµÄ×÷ÓñȽÏÓÐÏÞ¡£µ±È»£¬»¹ÊÇллÄúÁË£¡ 2016-08-31 12:37:40
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https://www.mathworks.com/help/d ... ss-fir-filters.html N = 100; % FIR filter order Fp = 20e3; % 20 kHz passband-edge frequency Fs = 96e3; % 96 kHz sampling frequency Rp = 0.00057565; % Corresponds to 0.01 dB peak-to-peak ripple Rst = 1e-4; % Corresponds to 80 dB stopband attenuation NUM = firceqrip(N,Fp/(Fs/2),[Rp Rst],'passedge'); % NUM = vector of coeffs fvtool(NUM,'Fs',Fs,'Color','White') % Visualize filter |
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jbb0523
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